我有桌子Tbl_Login
Cat_ID int Amount1 decimal Amount2 decimal Amount3 decimal dateon date Cat_ID Amount1 Amount2 Amount3 dateon 1 10 12 12 2013-02-12 2 10 12 12 2013-02-12 3 10 12 12 2013-02-12 4 10 12 12 2013-02-12 1 20 22 22 2013-02-13 2 20 22 22 2013-02-13 3 20 22 22 2013-02-13 5 20 22 22 2013-02-13 I want To Mamber Enter Two Date 12/02/2013 15/02/2013 and colum1 Cat_ID 12-02-2013 13-02-2013 14-02-2013 15-02-2013 Amount1 1 10 20 null null Amount2 1 12 22 null null Amount3 1 12 22 null null Amount1 2 10 20 null null Amount2 2 12 22 null null Amount3 2 12 22 null null Amount1 3 10 20 null null Amount2 3 12 22 null null Amount3 3 12 22 null null Amount1 4 10 null null null Amount2 4 12 null null null Amount3 4 12 null null null Amount1 5 null 20 null null Amount2 5 null 22 null null Amount3 5 null 22 null null
答案 0 :(得分:4)
您没有指定您正在使用的RDBMS,但有几种方法可以将此数据转换为您需要的结果。
如果您使用的数据库没有PIVOT
函数,则可以使用UNION ALL
查询来取消数据的转换,然后使用{{1的聚合函数表达式将日期转换为列。查询将类似于:
CASE
如果您使用的是SQL Server 2005+或Oracle 11g +,则可以同时使用select col,
cat_id,
max(case when dateon = '2013-02-12' then value end) [2013-02-12],
max(case when dateon = '2013-02-13' then value end) [2013-02-13],
max(case when dateon = '2013-02-14' then value end) [2013-02-14],
max(case when dateon = '2013-02-15' then value end) [2013-02-15]
from
(
select cat_id, 'amount1' col, amount1 value, dateon
from tbl_login
where dateon >= '2013-02-12'
and dateon <= '2013-02-15'
union all
select cat_id, 'amount2' col, cast(amount2 as decimal(10,2)) value, dateon
from tbl_login
where dateon >= '2013-02-12'
and dateon <= '2013-02-15'
union all
select cat_id, 'amount3' col, cast(amount3 as decimal(10,2)) value, dateon
from tbl_login
where dateon >= '2013-02-12'
and dateon <= '2013-02-15'
) src
group by col, cat_id
order by cat_id, col
和UNPIVOT
功能:
PIVOT
如果您要将未知数量的日期转换为列,则可以使用动态sql(注意:动态代码是sql server语法):
select col, cat_id,
[2013-02-12], [2013-02-13],
[2013-02-14], [2013-02-15]
from
(
select cat_id, dateon,
col, value
from
(
select cat_id, amount1,
cast(amount2 as decimal(10,2)) amount2,
cast(amount3 as decimal(10,2)) amount3,
dateon
from tbl_login
where dateon >= '2013-02-12'
and dateon <= '2013-02-15'
) s
unpivot
(
value
for col in (Amount1, Amount2, Amount3)
) unpiv
) src
pivot
(
max(value)
for dateon in ([2013-02-12], [2013-02-13],
[2013-02-14], [2013-02-15])
) piv
order by cat_id, col
所有查询的结果是:
DECLARE @cols AS NVARCHAR(MAX),
@query AS NVARCHAR(MAX),
@startdate datetime,
@enddate datetime
set @startdate ='2013-02-12'
set @enddate ='2013-02-15'
;with dates (dt) as
(
select @startdate
union all
select dateadd(dd, 1, dt)
from dates
where dateadd(dd, 1, dt) <= @enddate
)
select dt
into #temp
from dates
select @cols = STUFF((SELECT distinct ',' + QUOTENAME(convert(varchar(10), dt, 120))
from #temp
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
set @query = 'SELECT col, cat_id,' + @cols + '
from
(
select cat_id, dateon,
col, value
from
(
select cat_id, amount1,
cast(amount2 as decimal(10,2)) amount2,
cast(amount3 as decimal(10,2)) amount3,
dateon
from tbl_login
where dateon >= '''+convert(varchar(10), @startdate, 120)+'''
and dateon <= '''+convert(varchar(10), @enddate, 120)+'''
) s
unpivot
(
value
for col in (Amount1, Amount2, Amount3)
) unpiv
) src
pivot
(
max(value)
for dateon in (' + @cols + ')
) p
order by cat_id, col'
execute(@query)