我似乎无法将我的xml字符串解析为自定义对象。这是我的代码:
private Account parseXmlToAccount (String xml)
{
XDocument doc = XDocument.Parse(xml);
Console.Out.WriteLine("a" + xml);
List<Account> result =
(
from x in doc.Root.Elements("user")
select new Account()
{
Session = (string) x.Element("session").Value,
User = (string) x.Element("user").Value
}).ToList();
Console.Out.WriteLine("b");
return result.First();
和Account.cs:
class Account
{
public string Session { get; set; }
public string User { get; set; }
public override string ToString()
{
return Session + " " + User;
}
}
和我的xml字符串:
<user>
<session>7981239761293767891</session>
<user>873948797862364</user>
</user>
和我的错误消息:
UNHANDLED EXCEPTION: System.NullReferenceException: Object reference not set to an instance of an object
at testMonoAndroidApp.LoginManager.<parseXmlToAccount>m__4 (System.Xml.Linq.XElement) <0x00044>
at System.Linq.Enumerable/<CreateSelectIterator>c__Iterator27`2<System.Xml.Linq.XElement, testMonoAndroidApp.Account>.MoveNext () <0x0015b>
at System.Collections.Generic.List`1<testMonoAndroidApp.Account>.AddEnumerable (System.Collections.Generic.IEnumerable`1<testMonoAndroidApp.Account>) <0x000ab>
at System.Collections.Generic.List`1<testMonoAndroidApp.Account>..ctor (System.Collections.Generic.IEnumerable`1<testMonoAndroidApp.Account>) <0x00093>
at System.Linq.Enumerable.ToList<testMonoAndroidApp.Account> (System.Collections.Generic.IEnumerable`1<testMonoAndroidApp.Account>) <0x0003b>
at testMonoAndroidApp.LoginManager.parseXmlToAccount (string) <0x0012f>
...
答案 0 :(得分:3)
您的root是user
元素,因此请更改:
from x in doc.Root.Elements("user")
到
from x in doc.Elements("user")
答案 1 :(得分:3)
List<Account> result = (from o in doc.Elements()
select new Account{
User = o.Element("user").Value,
Session = o.Element("session").Value
}).ToList();