Question

以下脚本将返回两列。是否可以在显示文件名的列前添加另一列？

ls | select -First 10 |
% { 
    cat $_ | Select-String `, -AllMatches | 
        Select-Object LineNumber, @{n="Count"; e={$_.Matches.Count}} | 
        Group-Object Count | 
        % {
            New-Object psobject -Property @{
                "Count" = $_.Name
                "LineNumbers" = ($_.Group | Select-Object -ExpandProperty LineNumber) 
            }
        }
}

Count                                   LineNumbers                            
-----                                   -----------                            
77                                      {1, 2, 3, 4...}                        
78                                      {7, 15, 22, 43...}                     
79                                      {16, 32, 37, 90...}                    
77                                      {1, 2, 3, 4...}                        
78                                      {7, 15, 22, 43...}                     
79                                      {16, 32, 37, 90...}                    
77                                      {1, 2, 3, 4...}                        
78                                      {7, 15, 22, 43...}                     
79                                      {16, 32, 37, 90...}                    
77                                      {1, 2, 3, 4...}                        
78                                      {7, 15, 22, 43...}                     
79                                      {16, 32, 37, 90...}                    
77                                      {1, 2, 3, 4...}                        
78                                      {7, 15, 22, 43...}                     
79                                      {16, 32, 37, 90...}                    
77                                      {1, 2, 3, 4...}                        
78                                      {7, 15, 22, 43...}                     
79                                      {16, 32, 37, 90...}                    
89                                      {1, 2, 3, 4...}                        
89                                      {1, 2, 3, 4...}                        
89                                      {1, 2, 3, 4...}                        
89                                      {1, 2, 3, 4...}

Answer 1

试试这个（未经测试）：

ls | select -First 10 |
% {
    $filename = $_.Name 
    cat $_ | Select-String `, -AllMatches | 
        Select-Object LineNumber, @{n="Count"; e={$_.Matches.Count}} | 
        Group-Object Count | 
        % {
            New-Object psobject -Property @{
                "FileName" = $filename
                "Count" = $_.Name
                "LineNumbers" = ($_.Group | Select-Object -ExpandProperty LineNumber) 
            }
        }
}

如果您想要文件路径而不是文件名，请将第3行更改为$filename = $_.FullName

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