Question

我试图创建一个继承自超类中声明的元类的类，我确实喜欢这样：

from sqlalchemy import Column, String, create_engine
from sqlalchemy.ext.declarative import declarative_base
from sqlalchemy.orm import sessionmaker


class Database(object):
    """
        Class that holds all data models classes and functions
    """
    def __init__(self, wenDbPath = "test.db"):
        self.engine = create_engine('sqlite:///' + "c:/"+wenDbPath, echo=False)
        self.Session = sessionmaker(bind=self.engine)
        **self.Base** = declarative_base() # This returns a metaclass.
        self.Base.metadata.create_all(self.engine)
        self.session = self.Session()

    class Element(**self.Base**):
        __tablename__ = 'elements'
        idNumber = Column(String(255), primary_key=True)
        smallDiscription = Column(String(50), nullable=False)
        longDiscription = Column(String())
        webLink = Column(String())

        def __init__(self, idNumber, smallDiscription, longDiscription, webLink):
            self.idNumber = idNumber
            self.longDiscription = longDiscription
            self.smallDiscription = smallDiscription
            self.webLink = webLink
        def __repr__(self):
            return "<Element ('%s : %s')>" % (self.idNumber, self.smallDiscription)

Python给了我以下消息

class Element（self.Base）： NameError：名称'self'未定义

我该怎么办？

提前谢谢你。

Answer 1

在__init__运行之前评估一个类体。由于Base不依赖于__init__参数，因此您可以在课堂评估时对其进行评估：

class Database(object):
    ...
    Base = declarative_base() # This returns a metaclass.
    class Element(Base):
        ...

请注意，您使用Base作为超类，而不是元类;元类语法为__metaclass__ = Base或(metaclass=Base)，具体取决于版本。见What is a metaclass in Python?

我可以创建一个从这样的元类派生的子类吗？

1 个答案: