我的页面上有DropDownList
和提交按钮。 DropDownList
包含数据库中的数据列表,在从下拉列表中选择值然后单击“提交”按钮时,我在主视图页面的部分视图中获得所选下拉列表值的记录数。我的代码提供了正确的输出。我通过模型将View绑定到控制器。使用html.hiddenfor。
但每当我像往常一样点击提交按钮时,我的整个页面都会刷新。但我需要刷新部分视图而不是整页。
这是我正常运行的代码。但通过这段代码,我的整个页面都得到了刷新。我想阻止它。 :
查看:
<%@ Page Title="" Language="C#" MasterPageFile="~/Views/Shared/Site.Master" Inherits="System.Web.Mvc.ViewPage<ApricaCRMEvent.Models.CRM.DatabaseEntities.CRM_Doctor_Request>" %>
<asp:Content ID="Content1" ContentPlaceHolderID="TitleContent" runat="server">
MDLNoDDLIndex
</asp:Content>
<asp:Content ID="Content2" ContentPlaceHolderID="MainContent" runat="server">
<script type="text/javascript">
function TestFun() {
var mdlno = $("#ddlMDLNo").val();
var txtmdlno = document.getElementById("Request_For_Id");
txtmdlno.value = mdlno;
}
</script>
<div>
<h2>Search by MDLNo</h2>
<% using (Html.BeginForm())
{ %>
Select MDLno
<%= Html.DropDownList("ddlMDLNo", ViewData["MDLno"] as SelectList, "--Select One--", new { onchange = "TestFun()" })%>
<%: Html.HiddenFor(model => model.Request_For_Id) %>
<input type="submit" value="search" name="SearchMDLNo" id="btnclick" />
<% } %>
</div>
<div id="showtable"> //partial view
<% if (ViewBag.load == true)
{ %>
<%Html.RenderAction("MDLNoDataList"); %>
<% } %>
</div>
</asp:Content>
控制器:
// Search by mdl no
public ActionResult MDLNoDDLIndex()
{
ViewData["MDLno"] = new SelectList(CRMSearchReportDL.getAllMDLno(), "Request_For_Id", "Request_For_Id");
ViewBag.load = false;
return View();
}
[HttpPost]
public ActionResult MDLNoDDLIndex(CRM_Doctor_Request model)
{
ViewData["MDLno"] = new SelectList(CRMSearchReportDL.getAllMDLno(), "Request_For_Id", "Request_For_Id",model.Request_For_Id);
ViewBag.load = true;
return View();
}
public ActionResult MDLNoDataList()
{
List<CRM_Doctor_Request> drlist = new List<CRM_Doctor_Request>();
return PartialView(drlist);
}
[HttpPost]
public ActionResult MDLNoDataList(CRM_Doctor_Request model)
{
return PartialView(CRMSearchReportDL.getMDLNoWiseDetails(model.Request_For_Id));
}
答案 0 :(得分:3)
您可以使用jQuery为您执行此操作。在jQuery中捕获表单提交,而不是通过浏览器执行完整的表单发布,使用jQuery的.ajax()方法将表单数据提交给控制器操作。
这样的事情:
$.ajax({
url: urlToControllerAction,
data: {
ddlMDLNo: ddlMDLNo,
Request_For_Id: Request_For_Id
},
type: 'POST',
success: function (results) {
var partialData = $(results);
$('#showtable').html(partialData);
},
error: function (xhr, ajaxOptions, thrownError) {
// do something
}
});