所以我正在做一个项目,我必须从二进制数转换为小数等。 到目前为止这是我的代码,有一个bug。在二进制数中,例如1101,假设出来的十进制数是13,但是代码中出现的数字是11.这个错误发生在以一堆1开头并且像一个0开头的所有二进制数中。
import java.util.*; // imports everything in java.util
public class newCalculator{
* Conversion asks the user for a binary number. It converts the input to a decimal number
* using arrays and then displays the answer to the screen.
*/
public static void main (String[]args){ // creates the main method
binaryToDecimal(); //calls the user defined method binaryToDecimal
}
public static void binaryToDecimal() {
Scanner scan = new Scanner(System.in); // Creates a new Scanner
System.out.println("Input a Binary Number"); // Asks the user to input their number
String binary = scan.next(); // Creates a new String that stores the value of the input
char[] charArray = binary.toCharArray(); //Create a new Array and implements in the input
double answer = 0; // Creates a new double called answer setting it to zero
for (double index = 0; index < charArray.length; index++){//For loop
if (charArray[(int)index] == '1') {//If statement that allows the binary input to work
answer = answer + Math.pow(2.0, index);//Sets the answer with the math class power of 2
}
}
System.out.println(answer);//Prints out the final conversion result
/* Test Cases Expected Result Output
* 101 5 5
* 11 3 3
* 1 1 1
* 1101 13 11<--
* 111 7 7
* 1000001 65 65
* 1111 15 15
* 1001 9 9
* 11101 29 23<--
* 10101 21 21
*
*/
}
}
答案 0 :(得分:1)
正在计算您的预期结果,就好像从右到左读取二进制字符串一样;但是,您的代码是从左到右读取二进制字符串。
改变这个:
for (double index = 0; index < charArray.length; index++){
对此:
for (double index = charArray.length - 1; index >= 0; index--) {
您还应该更改为使用整数作为索引,如下所示:
for (int index = charArray.length - 1; index >= 0; index--) {
答案 1 :(得分:0)
你正在以错误的顺序查看你的位。您的第一个索引是指最重要的位,而不是最低位。
您对Math.pow的调用应为
answer = answer + Math.pow(2.0, (charArray.length - index - 1));
正如Tom Leese已经指出的那样,请使用整数作为循环索引。
答案 2 :(得分:0)
对称性就是答案。如果您查看所有测试输入,除1101
您的算法是正确的,除了index
中的Math.pow
而不是Math.pow(2.0, charArray.length - i - 1)
,您需要使用import java.util.Scanner;
public class NewCalc {
public static void main(String[] args) {
binaryToDecimal();
}
public static void binaryToDecimal() {
Scanner scan = new Scanner(System.in);
System.out.println("Input a Binary Number");
String binary = scan.next();
char[] charArray = binary.toCharArray();
double answer = 0;
for (int i = 0; i < charArray.length; i++) {
answer = charArray[i] == '1'
? answer + Math.pow(2.0, charArray.length - i - 1)
: answer;
}
System.out.println(answer);
}
}
,下面是正确的实现(实际上只是很小的增量更改)
{{1}}
答案 3 :(得分:0)
package pdaproject;
import java.util.Scanner;
public class NewCalc {
public static void main(String[] args) {
binaryToDecimal();
}
// convert to decimal (base 10)
public static void binaryToDecimal() {
Scanner scan = new Scanner(System.in);
System.out.println("Input a Binary Number");
String binary = scan.next();
int answer = 0;
// process left to right
for (int i = 0; i < binary.length(); i++) {
answer = 2 * answer + (binary.charAt(i) == '1' ? 1 : 0);
}
System.out.println(answer);
}
}
答案 4 :(得分:0)
public class BinaryToDecimal {
static int testcase1=1001;
public static void main(String[] args) {
BinaryToDecimal test = new BinaryToDecimal();
int result = test.convertBinaryToDecimal(testcase1);
System.out.println(result);
}
//write your code here
public int convertBinaryToDecimal(int binary)
{
int deci = 0;
int p=1;
int rem = 0;
while(binary>0)
{
rem = binary%10;
deci = deci+(rem*p);
p = p*2;
binary = binary/10;
}
return deci;
}
}