Question

我有一个Rails应用程序，我在其中使用delayed_job。我想检测一下我是否处于delayed_job进程中;

之类的东西

if in_delayed_job?
  # do something only if it is a delayed_job process...
else
  # do something only if it is not a delayed_job process...
end

但我无法弄清楚如何。这就是我现在正在使用的：

IN_DELAYED_JOB = begin
  basename        = File.basename $0
  arguments       = $*
  rake_args_regex = /\Ajobs:/

  ( basename == 'delayed_job' ) ||
  ( basename == 'rake' && arguments.find{ |v| v =~ rake_args_regex } )
end

另一种解决方案是，正如@MrDanA所说：

$ DELAYED_JOB=true script/delayed_job start
# And in the app:
IN_DELAYED_JOB = ENV['DELAYED_JOB'].present?

但他们是恕我直言的弱解决方案。任何人都可以提出更好的解决方案吗？

Answer 1

我处理这些的方式是通过一个偏执狂工人。我使用delayed_job进行上传到我网站的视频转码。在视频模型中，我有一个名为video_processing的字段，默认设置为0 / null。每当视频被delayed_job转码（无论是创建还是更新视频文件），它都将使用delayed_job中的钩子，并在作业开始时更新video_processing。作业完成后，完成的挂钩会将该字段更新为0。

在我的视图/控制器中，我可以video.video_processing? ? "Video Transcoding in Progress" : "Video Fished Transcoding"

Answer 2

也许是这样的。在您的类中添加一个字段，并在调用从延迟作业完成所有工作的方法时进行设置：

class User < ActiveRecord::Base
  attr_accessor :in_delayed_job

   def queue_calculation_request
     Delayed::Job.enqueue(CalculationRequest.new(self.id))
   end

   def do_the_work
     if (in_delayed_job)
       puts "Im in delayed job"
     else
       puts "I was called directly"
     end
   end

   class CalculationRequest < Struct.new(:id)
     def perform
       user = User.find(id)
       user.in_delayed_job = true
       user.do_the_work
     end

     def display_name
       "Perform the needeful user Calculations"
     end
   end
end

以下是它的外观：

来自延迟工作：

Worker(host:Johns-MacBook-Pro.local pid:67020)] Starting job worker
Im in delayed job
[Worker(host:Johns-MacBook-Pro.local pid:67020)] Perform the needeful user Calculations completed after 0.2787
[Worker(host:Johns-MacBook-Pro.local pid:67020)] 1 jobs processed at 1.5578 j/s, 0 failed ...

从控制台

user = User.first.do_the_work
  User Load (0.8ms)  SELECT "users".* FROM "users" WHERE "users"."id" = $1 LIMIT 1  [["id", 101]]
I was called directly

Answer 3

这对我有用：

def delayed_job_worker?
  (ENV["_"].include? "delayed_job")
end

Unix会将“_”环境变量设置为当前命令。

如果你有一个名为“not_a_delayed_job”的bin脚本，那就错了，但不要这样做。

Answer 4

ENV ['PROC_TYPE']如何左右只说到heroku ...但是当你是一个工人dyno时，这将被设置为'worker' 我用它作为“我在DJ中”

Answer 5

您可以为延迟的工作创建插件，例如在is_dj_job_plugin.rb目录中创建文件config/initializers。

class IsDjJobPlugin < Delayed::Plugin

  callbacks do |lifecycle|
    lifecycle.around(:invoke_job) do |job, *args, &block|
      begin
        old_is_dj_job = Thread.current[:is_dj_job]
        Thread.current[:is_dj_job] = true
        block.call(job, *args) # Forward the call to the next callback in the callback chain
        Thread.current[:is_dj_job] = old_is_dj_job
      end
    end
  end

  def self.is_dj_job?
    Thread.current[:is_dj_job] == true
  end
end

Delayed::Worker.plugins << IsDjJobPlugin

然后您可以通过以下方式进行测试：

class PrintDelayedStatus
  def run
    puts IsDjJobPlugin.is_dj_job? ? 'delayed' : 'not delayed'
  end
end

PrintDelayedStatus.new.run
PrintDelayedStatus.new.delay.run

检查我是否处于delayed_job进程中

5 个答案: