使用GroupBy函数从两个表中选择SELECT查询

Question

我正在使用Oracle APEX，我在查询如何制作它时有点困惑。我创建了两个具有以下属性的表

Employees(  "EMP_ID", 
    "EMP_NAME", 
    "EMP_DESIGNATION" , 
    "EMP_ADDRESS" , 
    "EMP_GENDER", 
    "EMP_CONTACT", 
    "EMP_EMAIL" , 
    "EMP_JOINING_DATE", 
     CONSTRAINT "PK_EMP_ID" PRIMARY KEY ("EMP_ID") ENABLE
   );`

和

Attendance
(   ATT_ID, 
    EMP_ID, 
    ATT_STATUS, 
    ATT_IN DATE, 
    ATT_OUT DATE, 
    ATT_COMMENTS, 
CONSTRAINT "PK_ATT_ID" PRIMARY KEY ("ATT_ID") ENABLE
CONSTRAINT "FK_EMP_ID" FOREIGN KEY ("EMP_ID") REFERENCES "EMPLOYEES" ("EMP_ID"));

我已从Att_Out中减去Att_In以获得我得到的MINUTES时间，然后multiply将.69与select emp_id,sum(((att_out-att_in)*1440)*.69) as "minutes*sal/m" from attendance group by emp_id; 相加，这是每分钟员工的工资在查询图中显示。

select EMP_ID,EMP_NAME

我想从Employees表INNER JOIN获取上面提到的其余查询。我使用group by，但后来{{1}}函数给了我错误。

Answer 1

试试这个

SELECT e.emplid, e.emp_name,  
sum(((a.att_out-a.att_in)*1440)*.69) as "minutes*sal/m"
FROM Employees e 
inner join attendance a on e.emplid = a.emplid
group by e.emplid, e.emp_name

Answer 2

尝试以下查询

select emp_id,sum(((att_out-att_in)*1440)*.69) as "minutes*sal/m" from attendance a,employees e 
where e.emp_id=a.emp_id
group by emp_id;

Answer 3

SELECT e.emp_id, e.emp_name, sum(((a.att_out-a.att_in)*1440)*.69) as "minutes*sal/m" 
FROM Employees e 
inner join attendance a on e.emp_id = a.emp_id 
group by e.emp_id, e.emp_name;

Answer 4

这可能对您有所帮助：

SELECT e.emplid, e.emp_name,  
sum(((a.att_out-a.att_in)*1440)*.69) as  employees_salary_per_minute
FROM Employees e 
inner join attendance a on e.emplid = a.emplid
group by e.emplid, e.emp_name