Question

我希望能够从两个SELECT查询中获取我在SUM（）中生成的两个值，并减去这些值以获得结果（OutstandingFunds）。

这是我的两个SELECT查询：

声明（1）：

SELECT SUM(Cf.Amount) AS ClearedFunds
FROM (
SELECT Amount FROM PAYMENT1 WHERE `Status` = "Cleared"
UNION ALL
SELECT Amount FROM PAYMENT2 WHERE `Status` = "Cleared"
UNION ALL
SELECT Amount FROM PAYMENT3 WHERE `Status` = "Cleared") AS Cf;

声明（2）：

SELECT SUM(Price) AS TotalSales
FROM PROPERTY
WHERE Status = “Sold”;

感谢您的时间

Answer 1

如果您不需要显示总销售额和清算资金的单独小计，您可以这样做：

SELECT SUM(Total.`Price`) AS ClearedFunds
FROM (
    SELECT `Price` FROM PROPERTY WHERE `Status` = 'Sold'
    UNION ALL
    SELECT (`Amount` * -1) AS `Price` FROM PAYMENT1 WHERE `Status` = 'Cleared'
    UNION ALL
    SELECT (`Amount` * -1) AS `Price` FROM PAYMENT2 WHERE `Status` = 'Cleared'
    UNION ALL
    SELECT (`Amount` * -1) AS `Price` FROM PAYMENT3 WHERE `Status` = 'Cleared'
) AS Total;

我假设你想在这里从总销售额中扣除已清算的资金。

Answer 2

你几乎就在那里......这是工作SQL：

SELECT (SELECT SUM(Cf.Amount) AS ClearedFunds
FROM (
SELECT Amount FROM PAYMENT1 WHERE `Status` = "Cleared"
UNION ALL
SELECT Amount FROM PAYMENT2 WHERE `Status` = "Cleared"
UNION ALL
SELECT Amount FROM PAYMENT3 WHERE `Status` = "Cleared") as Cf)

- (SELECT SUM(Price) AS TotalSales
FROM PROPERTY
WHERE Status = "Sold") as Result;

这是SQL小提琴，以便您可以使用测试数据：http://sqlfiddle.com/#!2/18677/11

Answer 3

在您的情况下，您可以使用SELECT ... INTO ...：

SELECT SUM(Cf.Amount) AS ClearedFunds
FROM (
SELECT Amount FROM PAYMENT1 WHERE `Status` = "Cleared"
UNION ALL
SELECT Amount FROM PAYMENT2 WHERE `Status` = "Cleared"
UNION ALL
SELECT Amount FROM PAYMENT3 WHERE `Status` = "Cleared") INTO @cf;

SELECT SUM(Price) AS TotalSales
FROM PROPERTY
WHERE Status = “Sold” INTO @ts;

然后你可以在任何其他查询中减去或使用它们，如下所示：

SELECT @ts - @cf;

Answer 4

你在找这个吗？

SELECT C.ClearedFunds - P.TotalSales
FROM (
SELECT SUM(Cf.Amount) AS ClearedFunds
FROM (
SELECT Amount FROM PAYMENT1 WHERE `Status` = "Cleared"
UNION ALL
SELECT Amount FROM PAYMENT2 WHERE `Status` = "Cleared"
UNION ALL
SELECT Amount FROM PAYMENT3 WHERE `Status` = "Cleared") AS Cf) C,
(SELECT SUM(Price) AS TotalSales
FROM PROPERTY
WHERE Status = “Sold”) P  
;

MySQL - 想要从两个SELECT语句中减去两个SUM（）值

4 个答案: