我有一个输出到文本文件的日历脚本。我正在打开文本文件,将其读入数组然后输出结果。文本文件包含:
7/9/2013-7/13/2013
Hot Stuff
By Robert More. Yes, folks, it's all platform shoes, leisure suits..
hotstuff.jpg
1,1,0,
*-*
7/16/2013-7/20/2013
Hot Stuff
By Robert More. Yes, folks, it's all platform shoes, leisure suits..
hotstuff.jpg
1,1,0,
*-*
我的PHP代码如下所示:
$content = file('DC_PictureCalendar/admin/database/cal2data.txt');
$content_chunked = array_chunk($content, 6);
if (count($content_chunked > 0))
{
echo "<table>";
for ($i=0;$i<count($content_chunked);$i++)
{
echo "<tr>";
echo "<td valign='top'>";
echo "<div style='padding-top:6px;'>";
echo "<a href='schedule.php'>";
echo "<img src='DC_PictureCalendar/admin/database/images/".$content_chunked[$i][3]."' width='80' height='80' border='2'>";
echo "</a>";
echo "</div>";
echo "</td>";
echo "<td valign='top'>";
echo "<div style='padding-left:5px;'>";
echo "<table>";
echo "<tr>";
echo "<td>";
echo "<h2>";
echo "<a href='schedule.php'>";
echo $content_chunked[$i][1];
echo "</a>";
echo "</h2>";
echo "</td>";
echo "</tr>";
echo "<tr>";
echo "<td>";
echo $content_chunked[$i][2];
echo "<a class='green' href='schedule.php'>";
echo "Read more..";
echo "</a>";
echo "</td>";
echo "</tr>";
echo "</table>";
echo "</div>";
echo "</td>";
echo "</tr>";
}
echo "</table>";
}
问题是,如果$ content_chunked [$ i] [1]中有重复的条目(在这种情况下是标题),我只想显示一次而不是两次。这可能吗?我认为array_unique可能会起作用,但似乎没有帮助。提前谢谢!
答案 0 :(得分:0)
array_unique()返回没有重复的数组,但不修改原始数组!
这样:
$a = [1, 1, 2, 3]
array_unique($a) => [1, 2, 3]
$a => [1, 1, 2, 3]
新数组需要保存在变量中,以便以后访问。
$a = [1, 1, 2, 3]
$b = array_unique($a)
$b => [1, 2, 3]
答案 1 :(得分:0)
虽然它可能不是最优雅/最有效的..在相关位置加入:
echo "<table>";
$titles = array();
for ($i=0;$i<count($content_chunked);$i++)
{
if (in_array($content_chunked[$i][1], $titles)) continue;
$titles[] = $content_chunked[$i][1]