SELECT t1.item_id, t1.item, t1.created, t1.owner, t1.type, t1.fld, t2.tag
FROM items AS t1
INNER JOIN tagged AS t2 ON t1.item_id = t2.item_id
WHERE tag
IN ('how', 'jkas', 'bodor', 'zimp', 'ctuo', 'sjex', 'kek'
)
GROUP BY item_id
ORDER BY t1.created DESC
LIMIT 0 , 100
如何根据他们与IN TAG的匹配数量来订购商品?我的手册非常深入,我找不到答案,我迷失了我不理解的东西。
答案 0 :(得分:1)
您可以使用COUNT
并将结果放在子查询中:
SELECT *
FROM (
SELECT t1.item_id, t1.item, t1.created, t1.owner,
t1.type, t1.fld, t2.tag, COUNT(DISTINCT t2.tag) tagCount
FROM items AS t1
INNER JOIN tagged AS t2 ON t1.item_id = t2.item_id
WHERE tag IN ('how', 'jkas', 'bodor', 'zimp', 'ctuo', 'sjex', 'kek')
GROUP BY item_id
) t
ORDER BY tagCount DESC, created DESC
LIMIT 0 , 100