Question

如何在webdriver中获取网页中的所有可用链接？

Answer 1

您可以使用以下逻辑获取所有链接。

List<WebElement> link=driver.findElements(By.tagName("a"));

for(WebElement ele:link)
{
     System.out.println(ele.getText());
}

Answer 2

    List<WebElement> list=driver.findElements(By.xpath("//a"));
    System.out.println("No of links present="+ list.size());

    // use of for loop for iteration
    for(int i=0;i<list.size();i++){
        System.out.println(list.get(i).getText());
    }
    System.out.println("-------------------------");
    //use of for each for iteration
    for(WebElement wb: list)
        System.out.println(wb.getText());

Answer 3

我同意Max.Mirkia，从'herf'获取网址

修改了Santoshsarma代码

 List<WebElement> tagName=driver.findElements(By.tagName("a"));
    for(WebElement ele:tagName)
    {
        String urls = ele.getAttribute("href");
        System.out.println(urls);
    }
}

Answer 4

List<WebElement> list=driver.findElements(By.cssSelector("a"));

for(WebElement link:list)                             
{
  System.out.println(link.getText());

}

需要使用webdriver获取所有可用链接

4 个答案: