我有两个字符串数组
order_items=["2832","3284","9832","9234"]
uri=["orderaccept/order_items/3284/cancel","orderaccept/order_items/9234/cancel"]
我想找到order_items
的所有元素,这些元素不属于uri
。在这种情况下,它应该返回2832
和9832
。
随意编辑两个数组的内容。我找不到类似的问题,但如果已经问过,请把我联系起来。
答案 0 :(得分:2)
order_items.select { |item| uri.none? { |u| u.include?(item) } }
答案 1 :(得分:2)
作为变体:
order_items.select{|i| !uri.join.include? i}
更新
order_items=["2832","3284","9832","9234"]
uri=["orderaccept/order_items/3284/cancel","orderaccept/order_items/9234/cancel"]
require 'benchmark'
joined = uri.join
n = 1_000_000
Benchmark.bm do |x|
x.report("select:") { n.times do order_items.select{|i| !uri.join.include? i}; end }
x.report("reject:") { n.times do order_items.reject{|i| uri.join.include? i}; end }
x.report("reject2:") { n.times do order_items.reject{|i| joined.include? i}; end }
x.report("none?:") { n.times do order_items.select { |item| uri.none? { |u| u.include?(item) } }; end }
x.report("substr:") { n.times do order_items - uri.map { |e| e.gsub /\D/, '' }; end }
x.report("subt+substr:") {n.times do order_items - uri.map { |i| i[24..27] }; end }
end
它产生了
user system total real
select: 4.181000 0.015000 4.196000 ( 4.275000)
reject: 3.931000 0.000000 3.931000 ( 3.925000)
reject2: 1.388000 0.000000 1.388000 ( 1.440000)
none?: 4.462000 0.000000 4.462000 ( 4.490000)
substr: 26.582000 0.016000 26.598000( 26.675000)
subt+substr: 3.167000 0.000000 3.167000 ( 3.170000)
答案 2 :(得分:0)
我猜数组减法在这里更适用,因为它对未来的代码修订是自我描述的(你确实愿意从数组中减去不必要的项目,不是吗?)
order_items - uri.map { |e| e.gsub /\D/, '' }
UPD Ooups ......基准测试迫使我准确思考,例如它来到:
order_items - uri.map { |i| i[24..27] }
基准:
order_items=["2832","3284","9832","9234"]
uri=["orderaccept/order_items/3284/cancel","orderaccept/order_items/9234/cancel"]
require 'benchmark'
n = 1_000_000
Benchmark.bm do |x|
x.report("select:") { n.times do order_items.select{|i| !uri.join.include? i}; end }
x.report("reject:") { n.times do order_items.reject{|i| uri.join.include? i}; end }
x.report("none?:") { n.times do order_items.select { |item| uri.none? { |u| u.include?(item) } }; end }
x.report("subt+gsub:") { n.times do order_items - uri.map { |e| e.gsub /\D/, '' }; end }
x.report("subt+substr:") {n.times do order_items - uri.map { |i| i[24..27] }; end }
end
产量:
user system total real
select: 7.200000 0.000000 7.200000 ( 7.206846)
reject: 6.240000 0.000000 6.240000 ( 6.253924)
none?: 9.230000 0.020000 9.250000 ( 9.282425)
subt+gsub: 43.440000 0.000000 43.440000 ( 43.491133)
subt+substr: 5.320000 0.010000 5.330000 ( 5.333616)