Question

我想在我的类中覆盖数组索引运算符。这是我想要做的，但没有成功。

class Complex{              
    Complex const& operator[](unsigned int) const; // Read-only access
    Complex& operator[](unsigned int);             // Read/Write access:
};

const Complex& Complex::operator [](unsigned int unsignedInt) const {
    const Complex* temp = this+i;
    return *temp;
}
Complex& Complex::operator [](unsigned int unsignedInt) {
    Complex* temp = this+i;
    return *temp;
}

编辑：我想做点什么：

Complex **c = new Complex[5];    //Create 2D array
c[2] = new Complex();            //Initialize
cout<<*c[2];                     //print by overloading <<

Answer 1

您的函数定义语法错误：

Complex Complex::const& operator[](unsigned int i) const{

返回类型应该由const&注释，显式名称限定Complex::属于函数名称operator[]：

Complex const& Complex::operator[](unsigned int i) const {

此外，实现似乎是错误的：

const Complex* temp = this+i;
return *temp;

这没有多大意义。你可能的意思是：

Complex temp = *this + i;
return temp;

假设适当的operator+超载。虽然很难说你真正想要哪种语义，因为无论如何都没有Complex的直观索引访问。

Answer 2

而不是

Complex Complex::const& operator[](unsigned int i) const

应该是

const Complex& Complex::operator[](unsigned int i) const

覆盖数组索引运算符

2 个答案: