如何读取Android应用中的文本文件:
"1.something written
2.in this file
3.is to be read by
4.the InputStream
..."
所以我可以返回一个字符串,如:
"something written\nin this file\nis to be read by\nthe InputStream"
我想到的是(伪代码):
make an inputstream
is = getAssest().open("textfile.txt"); //in try and catch
for loop{
string = is.read() and if it equals "." (i.e. from 1., 2., 3. etc) add "/n" ...
}
答案 0 :(得分:28)
试试这个
import android.app.Activity;
import android.os.Bundle;
import android.widget.Toast;
import java.io.*;
public class FileDemo1 extends Activity {
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
try {
playWithRawFiles();
} catch (IOException e) {
Toast.makeText(getApplicationContext(), "Problems: " + e.getMessage(), 1).show();
}
}
public void playWithRawFiles() throws IOException {
String str = "";
StringBuffer buf = new StringBuffer();
InputStream is = this.getResources().openRawResource(R.drawable.my_base_data);
try {
BufferedReader reader = new BufferedReader(new InputStreamReader(is));
if (is != null) {
while ((str = reader.readLine()) != null) {
buf.append(str + "\n" );
}
}
} finally {
try { is.close(); } catch (Throwable ignore) {}
}
Toast.makeText(getBaseContext(), buf.toString(), Toast.LENGTH_LONG).show();
}
}
答案 1 :(得分:12)
使用BufferedReader
读取输入流。由于BufferedReader
将从字符输入流中读取文本,因此缓冲字符以便有效地读取字符,数组和行。 InputStream
表示输入的字节流。 reader.readLine()
将逐行读取文件。
BufferedReader reader = new BufferedReader(new InputStreamReader(in));
StringBuilder out = new StringBuilder();
String line;
while ((line = reader.readLine()) != null) {
out.append(line); // add everything to StringBuilder
// here you can have your logic of comparison.
if(line.toString().equals(".")) {
// do something
}
}
答案 2 :(得分:1)
File fe=new File(abc.txt);
FileInputStream fis=new FileInputStream(fe);
byte data[]=new byte[fis.available()];
fis.read(data);
fis.close();
String str=new String(data);
System.out.println(str);