Question

代码很好地说明了问题，我已经削减了一切无关的内容。

游戏开始时创建2-4个亲属

function createInitialKinsmen()
{
    for (var k:int = 1; k < 3 + Math.round(Math.random() * 2; k++)
    {
        if (k == 1)
        {
            createKinsmen(0);
            trace ("player");
        }
        else
        {
            createKinsmen(1);
            trace ("starting kinsmen");
        }
    }
}

亲属创建功能

function createKinsmen(arrivalTypeVar:int)
{
    var newKinsmen = new kinsmen;
    listPanel.kinsmenDivider.addChild(newKinsmen);
    totalKinsmen++;
    totalKinsmenAlive++;
    newKinsmen.name = "kinsmen" + totalKinsmen;
    newKinsmen.arrivalType = arrivalTypeVar;
}

Kinsmen课程

public class kinsmen extends MovieClip
{
    var arrivalType:int;
    function kinsmen()
    {
        trace(this.name);
        if (this.arrivalType = 0)
        {
            trace("player");
        }
        if (this.arrivalType = 1)
        {
            trace("starting kinsmen");
        }
    }
}

输出应该说：

kinsmen1
player
player
kinsmen2
starting kinsmen
starting kinsmen
kinsmen3
starting kinsmen
starting kinsmen
kinsmen4
starting kinsmen
starting kinsmen

但反而说：

kinsmen1
player
player
kinsmen2
player
starting kinsmen
kinsmen3
player
starting kinsmen
kinsmen4
player
starting kinsmen

这意味着 arrivalType 变量未被传递。似乎是硬编码的变量可以通过，因此此刻我在kinsmen movieclip中有一个alpha 0的正方形，它的x位置决定了构造函数中 arrivalType 的值但是这肯定可以不是很好的做法，有没有更好的方法呢？

Answer 1

我认为您只想修改kinsmen类的构造函数，以接受arrivalType和name的参数。

您目前正在做的是构建一个新的kinsmen对象，然后在该对象上设置arrivalType和name。因此，当构造函数代码运行时，arrivalType是int的默认值，即0。

在kinsmen类中修改你的构造函数：

function kinsmen(arrivalType:int, name:String)
{
    this.name = name;
    this.arrivalType = arrivalType;
    if (this.arrivalType == 0)
    {
        trace("player");
    }
    if (this.arrivalType == 1)
    {
        trace("starting kinsmen");
    }
}

修改您的createKinsmen()函数，以便将arrivalType的值传递给构造函数方法，而不是在对象之后设置arrivalType和name创建：

function createKinsmen(arrivalTypeVar:int)
{
    totalKinsmen++;
    totalKinsmenAlive++;
    var newKinsmen = new kinsmen(arrivalTypeVar, "kinsmen" + totalKinsmen);
    listPanel.kinsmenDivider.addChild(newKinsmen);
}

如何将变量传递给新孩子？ [flash AS3]

1 个答案: