Question

我有EF类，我为每个人创建了模型（没有来自EF poco类的继承），具有各种DAL功能（get，set，order等等）。 BL将在控制器内部。单个模型实例的一切看起来都很好，但现在我需要绑定才能查看数据列表。以下是我如何做到的一个例子。我是MVC的新手，并不确定这是否是最好的做法：

型号：

public class CustomerWishlistModel
{
    static storeDataEntities db = new storeDataEntities();

    //Some properties of the model
    public int CustomerID { get; set; }

    public int ProductID { get; set; }

    public string ProductName { get; set; }

    public string BrandName { get; set; }

    public CustomerWishlistModel(){}

    //Get wishlists by customer
    public static List<CustomerWishlist> GetCustomerWishLists(int customerID)
    {
         return db.CustomerWishlists.Where(x => x.CustomerID == customerID).ToList();
    }

    //Convert wishlist to model
    public static CustomerWishlistModel GetWishListModel(CustomerWishlist thisWishList)
    {  
        CustomerWishlistModel thisWishListModel = new CustomerWishlistModel()
        {
            CustomerID = thisWishList.CustomerID,
            ProductID = thisWishList.ProductID,
            BrandName = thisWishList.Product.Supplier.BrandName,
            ProductName = thisWishList.Product.Name
       };

       return thisWishListModel;
    }
}

控制器：

[Authorize]
[HttpGet]
public ActionResult Index(string id)
{
    //Get all wishlists to current customer
    List<CustomerWishlist> thisWishList = CustomerWishlistModel.GetCustomerWishLists(int.Parse(id));

    //Get language from url
    Language thisLanguage = LanguageModel.GetLanguageByCulture(RouteData.Values["language"].ToString());

    if (Session["UserID"] != null && Session["UserID"].ToString() == id && thisWishList != null && thisLanguage != null)
    {
        List<CustomerWishlistModel> thisWishlistModel = new List<CustomerWishlistModel>();

        //Get all wishlists that their status is online and language equals to current
        foreach (CustomerWishlist item in thisWishList)
        {
            if (item.Product.Status == (int)EnumModel.ProductStatus.Online && item.Product.LanguageID == thisLanguage.ID)
            {
                thisWishlistModel.Add(CustomerWishlistModel.GetWishListModel(item));
            }
        }

        return View(thisWishlistModel);
    }
    else
    {
        return RedirectToAction("Login", "Customer");
    }
}

视图：

@model IEnumerable<Store.Models.CustomerWishlistModel>
@{
    Layout = "~/Views/Shared/_Layout.cshtml";
    ViewBag.Title = Resources.Store.WishList;    
}
@using (Html.BeginForm())
{
    <h2>@Resources.Store.WishList</h2>

    foreach (Store.Models.CustomerWishlistModel item in Model.ToList())
    {
         item.BrandName...... and other markup tags
    }
}

Answer 1

最佳做法是从控制器中删除任何业务逻辑，它们只是处理调用适当的服务并将模型数据传递给视图。您的模型不应该有任何数据访问代码，而是最好将收集数据抽象到另一个类并返回一个干净的模型。例如，抽象DAL最流行的模式之一是通过简单接口（如Customer CustomerRepository.GetCustomer(int id)）返回数据的存储库模式。

所有业务逻辑也应包含在服务中，这些服务将调用存储库以获取所需数据，并根据业务规则处理数据。该服务将返回一个干净的模型对象，您的控制器将传递给该视图。简单干净。

ASP.NET MVC ViewModel用于集合的最佳实践

1 个答案: