Question

人：

Id  Name
1   Anton
2   Ib
3   Knud
4   Hans

注册

Id  PersonId    Status  DateTime        Department
5   1           1       11-1-2013 10:00 1
6   1           0       10-1-2013 09:00 1
7   1           2       10-1-2013 14:05 1
8   1           2       09-1-2013 09:00 1
9   2           2       09-1-2013 09:00 2
10  3           2       09-1-2013 09:00 3
11  4           2       10-1-2013 17:00 1

我需要选择部门1当天（10-1-2013）的最新注册（个人）

预期输出：

Name    R.Id    P.Id    Status  DateTime        Department

Anton   7       1       2       10-1-2013 14:05 1
Hans    11      4       2       10-1-2013 17:00 1

Answer 1

我想你只想要这个：

select top 1 p.name, r.id, p.id, r.status, r.datetime, r.department
from registration r join
     person p
     on r.personid = p.personid
where department = 1 and cast(daTetime as date) = '10-1-2013'
order by datetime desc

部门的最新注册，而不是个人。这只是使用where子句按日期和部门过滤，按datetime列排序并选择第一个。

获得所有这些：

select p.name, r.id, p.id, r.status, r.datetime, r.department
from (select r.*, row_number() over (partition by person order by datetime desc) as seqnum
      from registration r
      where department = 1 and cast(daTetime as date) = '10-1-2013'
     ) r join
     person p
     on r.personid = p.personid
where seqnum = 1
order by datetime desc

在与人一起加入时，需要按部门选择最新的注册

1 个答案: