Question

我正在尝试使用以下代码来处理通过我的网站与客户联系。它无法正常工作并且错误被捕获。收到的消息“抱歉，意外错误。请稍后再试”。

下面包含html表单和php处理程序。两者都在单独的页面中，分别是contact.php和contact_handle.php。

形式：

  <div id="contact-form">
                <form method="post" action="contact_handle.php">

                    <div class="field">
                        <label>Name:</label>
                        <input type="text" name="name" class="text" />
                    </div>

                    <div class="field">
                        <label>Email: <span>*</span></label>
                        <input type="text" name="email" class="text" />
                    </div>

                    <div class="field">
                        <label>Subject: <span>*</span></label>
                        <input type="text" name="subject" class="text" />
                    </div>

                    <div class="field">
                        <label>Mobile No: <span>*</span></label>
                        <input type="text" name="mobile" class="text" />
                    </div>

                    <div class="field">
                        <label>Message: <span>*</span></label>
                        <textarea name="message" class="text textarea" ></textarea>
                    </div>

                    <div class="field">
                        <input type="button" id="send" value="Send Message"/>
                        <div class="loading"></div>
                    </div>

                </form>
</div

现在处理程序是：

<?php

//Retrieve form data. 
//GET - user submitted data using AJAX
//POST - in case user does not support javascript, we'll use POST instead
$name = ($_GET['name']) ? $_GET['name'] : $_POST['name'];
$email = ($_GET['email']) ?$_GET['email'] : $_POST['email'];
$subject = ($_GET['subject']) ?$_GET['subject'] : $_POST['subject'];
$mobile = ($_GET['mobile']) ?$_GET['mobile'] : $_POST['mobile'];
$message = ($_GET['message']) ?$_GET['message'] : $_POST['message'];

//flag to indicate which method it uses. If POST set it to 1
if ($_POST) $post=1;

//Simple server side validation for POST data, of course, you should validate the email
if (!$name) $errors[count($errors)] = 'Please enter your name.';
if (!$email) $errors[count($errors)] = 'Please enter your email.'; 
if (!$subject) $errors[count($errors)] = 'Please enter your subject.';
if (!$mobile) $errors[count($errors)] = 'Please enter your mobile No.';
if (!$message) $errors[count($errors)] = 'Please enter your message.'; 

//If the errors array is empty, send the mail
if (!$errors) {

    // ====== Your mail here  ====== //
    $to = 'fsa@gmail.com';

    // Sender
    $from = $name . ' <' . $email . '>';

    //subject and the html message
    $subject = 'Message from www.iso.com contact form'; 
    $message = '
    <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" 
    "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
    <html xmlns="http://www.w3.org/1999/xhtml">
    <head></head>
    <body>
    <table>
        <tr><td>Name:</td><td>' . $name . '</td></tr>
        <tr><td>Email:</td><td>' . $email . '</td></tr>
        <tr><td>Subject:</td><td>' . $subject . '</td></tr>
        <tr><td>Mobile No.:</td><td>' . $mobile . '</td></tr>
        <tr><td>Message:</td><td>' . nl2br($message) . '</td></tr>
    </table>
    </body>
    </html>';

    // Send the mail
    $result = sendmail($to, $subject, $message, $from);


    //if POST was used, display the message straight away
    if ($_POST) {
        if ($result) echo 'Thank you! We have received your message.';
        else echo 'Sorry, unexpected error. Please try again later';

    //else if GET was used, return the boolean value so that 
    //ajax script can react accordingly
    //1 means success, 0 means failed
    } else {
        echo $result;   
    }

// If the errors array has values
} else {}


// Simple mail function with HTML header
function sendmail($to, $subject, $message, $from) {
    $headers = "MIME-Version: 1.0" . "\r\n";
    $headers .= "Content-type:text/html;charset=iso-8859-1" . "\r\n";
    $headers .= 'From: ' . $from . "\r\n";

    $result = mail($to,$subject,$message,$headers);

    if ($result) return 1;
    else return 0;
}

?>

我希望你能帮助发现我错过的错误。

非常感谢：）

Answer 1

mail()功能仅与服务器上安装的邮件传输一样可靠。在这种情况下，您应该检查服务器的邮件日志，以获取有关邮件未被接受的原因的信息。

此外，如果您不确定该信息是通过$_GET还是$_POST进来的，那么您只需使用$_REQUEST，这是两者的混合，加上{{1}如果记忆为我服务。

Answer 2

检查服务器的PHP错误日志（具体取决于您的服务器设置）。它将为您提供更多信息。

那就是说，根据您在这里提供的信息，我冒昧地猜测您对sendmail()的呼叫失败了。最可能的原因是您的服务器上没有安装PHP使用的邮件发件人。

您需要确保设置了邮件发件人程序，或者使用SMTP与其他邮件客户端（例如Gmail帐户）进行发送。

php：从联系人发送邮件不断抛出错误

2 个答案: