Question

我需要将日期字符串-'2013-01-01'转换为数字--20130101类型。如何有效地在Oracle中完成它？

    My Input-

'2013-01-01'

   My Output

    Output-20130101

Answer 1

select to_number(replace('2013-01-01', '-')) from dual;

Answer 2

   to_char(your_date,'YYYYMMDD')

这里使用带有日期的to_char的基础知识。

Answer 3

您可以将字符串转换为日期并使用您想要的格式转换回来：

select to_char(to_date('2013-01-01', 'YYYY-MM-DD'), 'YYYYMMDD');

有关日期时间格式的更多信息：

http://docs.oracle.com/cd/B19306_01/server.102/b14200/sql_elements004.htm

Answer 4

您还可以“利用”格式掩码：

select to_number('2013-01-01', '9999G99G99', 'nls_numeric_characters=,-')
from dual

Here is a sqlfiddle demo

Answer 5

要将日期字符串转换为数字：

始终先将其转换为char然后转换为数字：

SEQUENCE    CHECK_TIME  DEVICE  ORIGIN  NAMESPACE   SERVICE_CHECK   VALUE   TAGS
0   2020-06-24T02:00:05.441Z    kubeflow-vm vm.azm.ms/map   Computer    Heartbeat   1   {"vm.azm.ms/processIds":["p-96566f30b8066a6479008755c528d7920511edc8","p-9f6667971df49fed675576b8f936cc45a61d242d","p-cfc973bcf0a32b902410a7b16cd977d6bb264e62","p-39a51e264bf790ec9e4a6902ead00101c1e78c97","p-d63478488b88c35f85a2c11e07642dddec84ef62","p-ce8cf40e9b45c9db18007f181460e21587af3267","p-e2643b874c714b4dd182003298ad59268f7f6b5b","p-0efa4aa396315bfcd87632237460ab0c12124c46","p-642d2b7e86ff01c62bc11f858e074e741d54d37b","p-0a3fbb9d81230bee9daaa2ce8262bb5357debb69","p-f61381ae6a9c8cdad1f241c9c456015658a8f925","p-f3f604a0313bc1778e69c9203a0162d1abfedad2","p-6dec6d0558740906471b6d3ee920cce37faeca70","p-27613669fcf7faaeef5023acc6505973e12d2db5","p-d97d079b692dcb81adb5ed5dc48d29c82ef6f93a","p-44507943475c4fb04f09595617020da7ac2c388c"]}

如果您的列数据类型为DATE，则在下面使用您的列名代替sysdate：

Select TO_NUMBER(TO_CHAR(to_date('2013-01-01', 'YYYY-MM-DD'),'YYYYMMDD')) from dual

将oracle日期字符串转换为数字

5 个答案: