Question

Rails项目：Project有很多Ticket个。

修改故障单的路径：/projects/12/tickets/11/edit

更新故障单并验证失败时，我使用render :action => "edit"。

但是，当编辑视图呈现此时间时，路径将更改为/tickets/11/

这意味着我失去了一些参数。我怎样才能保留原始路径？

routes.rb中：

  resources :projects do
    resources :tickets
  end
  resources :tickets

tickets_controller.rb

  def new
    @ticket = Ticket.new
  end

  def create
    @ticket = Ticket.new(params[:ticket])
    @ticket.user_id = session[:user_id]

    respond_to do |format|
      if @ticket.save
        format.html { redirect_to project_path(@ticket.project), :notice => "Ticket was created." }
      else
        format.html { render :action => "new" }
      end
    end
  end

  def edit
    @ticket = Ticket.find(params[:id])
  end

  def update
    @ticket = Ticket.find(params[:id])
    respond_to do |format|
      if @ticket.update_attributes(params[:ticket])
        format.html { redirect_to project_ticket_path(@ticket.project, @ticket), :notice => "Ticket was updated." }
      else
        format.html { render :action => "edit" }
      end
    end
  end

Answer 1

你要两次调用资源。如果您不想“丢失一些参数”，请删除第二个参数。

resources :projects do
  resources :tickets
end

但是，如果您希望resources :tickets非嵌套，则可以将其限制为仅show和index，以避免在创建和编辑时丢失某些参数。

resources :projects do
  resources :tickets
end
resources :tickets, :only => [:index, :show]

编辑 - 我认为问题出在你的形式上确保你有两个对象：

form_for([@project, @ticket]) do |f|

此外，在创建或更新project之前，您必须找到ticket。因此，您的new和edit操作必须具有以下内容：

@project = Project.find(params[:project_id])
@ticket = @project.ticket.build

和create操作相同：

@project = Project.find(params[:project_id])
@ticket = @project.ticket.build(params[:ticket])

edit2 - 您的更新操作应该是：

@project = Project.find(params[:project_id])
@ticket = Ticket.find(params[:id])
if @ticket.update_attributes(params[:ticket])
...

Answer 2

看看http://guides.rubyonrails.org/routing.html#nested-resources。您应该能够使用嵌套路由助手（例如project_ticket_path(@project, @ticket)）从控制器重定向到嵌套资源。

RoR：更新动作。错误时渲染路径

2 个答案: