Question

{
  "data": [{
    "data": [{
      "Part": "1.75 L ICON (Glass)",
      "ProductionCounts": 1012620
    }, {
      "Part": "1.75 L Marg Mix (PET)",
      "ProductionCounts": 1003278
    }, {
      "Part": "1.75 L Authentics (PET)",
      "ProductionCounts": 457615
    }, {
      "Part": "1.0 L Margarita Mix / PET",
      "ProductionCounts": 660982
    }, {
      "Part": "other",
      "ProductionCounts": 1571985
    }]
  }, ],
  "dateArray": ["2011-01-01", "2011-02-01", "2011-03-01", "2011-04-01", "2011-05-01", "2011-06-01", "2011-07-01", "2011-08-01", "2011-09-01", "2011-10-01", "2011-11-01"],
  "xAxis": "Part",
  "yAxis": "ProductionCounts",
  "interestingMoments": []
}

我想访问json对象的值。每次获取json对象时，json对象的字段名称都会不同，因此我将xAxis和yAxis中的字段名称作为单独发送。

当我尝试访问jsonData.data [0] .data [0] .xAxis时，它给了我undefined而不是value。我无法像这样访问，因为每次字段名称都不同，所以我试图通过变量jsonData.data [0] .data [0] .Part。

来访问它。

Answer 1

jsonData.data[0].data[0][jsonData.xAxis]和jsonData.data[0].data[0][jsonData.yAxis]

http://jsfiddle.net/vsZkR/

Answer 2

你应该像这样使用json

var a = {
  "data": [{
    "data": [{
      "Part": "1.75 L ICON (Glass)",
      "ProductionCounts": 1012620
    }, {
      "Part": "1.75 L Marg Mix (PET)",
      "ProductionCounts": 1003278
    }, {
      "Part": "1.75 L Authentics (PET)",
      "ProductionCounts": 457615
    }, {
      "Part": "1.0 L Margarita Mix / PET",
      "ProductionCounts": 660982
    }, {
      "Part": "other",
      "ProductionCounts": 1571985
    }]
  }, ],
  "dateArray": ["2011-01-01", "2011-02-01", "2011-03-01", "2011-04-01", "2011-05-01", "2011-06-01", "2011-07-01", "2011-08-01", "2011-09-01", "2011-10-01", "2011-11-01"],
  "xAxis": "Part",
  "yAxis": "ProductionCounts",
  "interestingMoments": []
};

a.data[0].data[0][a.xAxis] // for access part values
a.data[0].data[0][a.yAxis]  // for acsess ProductionCounts values

Answer 3

对于xAxis，这应该可行：

console.log( jsondata.xAxis );

见这里：jsFiddle

Answer 4

试试这个：

var data={
  "data": [{
    "data": [{
      "Part": "1.75 L ICON (Glass)",
      "ProductionCounts": 1012620
    }, {
      "Part": "1.75 L Marg Mix (PET)",
      "ProductionCounts": 1003278
    }, {
      "Part": "1.75 L Authentics (PET)",
      "ProductionCounts": 457615
    }, {
      "Part": "1.0 L Margarita Mix / PET",
      "ProductionCounts": 660982
    }, {
      "Part": "other",
      "ProductionCounts": 1571985
    }]
  }, ],
  "dateArray": ["2011-01-01", "2011-02-01", "2011-03-01", "2011-04-01", "2011-05-01", "2011-06-01", "2011-07-01", "2011-08-01", "2011-09-01", "2011-10-01", "2011-11-01"],
  "xAxis": "Part",
  "yAxis": "ProductionCounts",
  "interestingMoments": []
};
console.log(data.xAxis);
console.log(data.yAxis);

Answer 5

我会从冗余的“数据”对象中解开它。

http://jsfiddle.net/turiyag/cQNPm/

之后它看起来更干净，并且工作得很好。您的JSON对象也失败了JSLint。在发布此处之前，始终通过JSLint或类似产品运行您的代码。

log("jsonData.data[0][jsonData.yAxis]: " + jsonData.data[0][jsonData.yAxis]);

通过变量访问json对象值

5 个答案: