mysql - group，但显示列的所有行

Question

我想对字段进行分组，但希望显示名为remain的列的所有行：

这是没有分组的当前输出：

并以群组输出：

当我分组时我想要这个：

这是mysql查询：

SELECT staff.name,
  staff.designation_id_designation,
  staff.status_id_status,
  Concat_Ws('=', leave_remain.leave_type_id_leave_type, leave_remain.days) AS
  remain
FROM staff INNER JOIN
  leave_remain ON staff.id_staff = leave_remain.staff_id_staff
GROUP BY staff.name    

Answer 1

使用GROUP_CONCAT

SELECT  staff.name,
        staff.designation_id_designation,
        staff.status_id_status,
        GROUP_CONCAT(Concat_Ws('=', leave_remain.leave_type_id_leave_type, leave_remain.days)) AS remain
FROM    staff 
        INNER JOIN leave_remain 
            ON staff.id_staff = leave_remain.staff_id_staff
GROUP   BY staff.name, staff.designation_id_designation, staff.status_id_status  

• SQLFiddle Demo

其他链接

• MySQL GROUP_CONCAT

Answer 2

试试这个：

SELECT staff.name,
  staff.designation_id_designation,
  staff.status_id_status,
  GROUP_CONCAT(Concat_Ws('=', leave_remain.leave_type_id_leave_type, leave_remain.days) SEPARATOR ' ') AS remain
FROM staff INNER JOIN
  leave_remain ON staff.id_staff = leave_remain.staff_id_staff
GROUP BY staff.designation_id_designation,
         staff.name,
         staff.status_id_status;

Answer 3

为此我们需要使用由''分隔的group_concat。

SELECT staff.name,
  staff.designation_id_designation,
  staff.status_id_status,
  GROUP_CONCAT(Concat_Ws('=', leave_remain.leave_type_id_leave_type, leave_remain.days) SEPARATOR ' ') AS remain
FROM staff 
INNER JOIN
  leave_remain 
ON 
staff.id_staff = leave_remain.staff_id_staff
GROUP BY staff.designation_id_designation,
         staff.name,
         staff.status_id_status;