Question

下面我在表“test”中插入一个值，并成功检索新行的@@ identity。然后我将一个值插入表test2（成功），但检索到的@@ identity始终为“0”。获取第二个@@身份有什么问题？我该如何解决这个问题？

Sub GoDo()

Dim testIdentity As Integer
Dim test2Indentity As Integer

Dim name As String
Dim concept As String

name = Cells(1, 1)
concept = Cells(1, 2)


Dim cn As New ADODB.Connection
Dim rs As New ADODB.Recordset
Dim rs2 As New ADODB.Recordset

cn.ConnectionString = "Provider=SQLOLEDB;Data Source=MARS;Initial Catalog=automation;Trusted_connection=yes;"
cn.Open

cn.Execute ("INSERT INTO test(data) VALUES ('" & name & "')")
rs.Open "SELECT @@identity AS NewID", cn
testIdentity = rs.Fields("NewID")
rs.Close

cn.Execute ("INSERT INTO test2(data) VALUES ('" & concept & "')")
rs2.Open "SELECT @@identity AS NewID", cn
testIdentity = rs2.Fields("NewID")
rs2.Close

cn.Execute ("INSERT INTO test3(test_id, test2_id) VALUES ('" & testIdentity & "','" & test2Indentity & "')")

cn.Close

End Sub

结果例如：INSERT INTO Test3（test_id，test2_id）VALUES（'18'，'0'）

Answer 1

怎么样：

sql = "INSERT INTO test(data) VALUES ('" & name & "');" & _
      "SELECT NewID = SCOPE_IDENTITY();"
SET rs = cn.Execute (sql)
testIdentity = rs.Fields("NewID")

现在说，你至少应该使用参数化语句，或者更好的是存储过程。此外，我不确定为什么在插入数字值时会在数字值周围加上单引号。您是否将数字存储为字符串？为什么？如果没有，你为什么要把它们当成字符串？

VBA INSERT和@@ Identity（第二次插入新表时无法获得@@ Identity）

1 个答案: