Question

如何使用代码

创建多个客户端

Program.cs的

class Program
{
    static void Main(string[] args)
    {
        Server.ServerCode(5656);
    } 
}

Client.cs

class Client
{
    public static void ClientCode()
    {
            //SOCKET CONNECTION

            //int Port = (int)port;
            Console.WriteLine("......................CLIENT.........................");

            TcpClient client = new TcpClient("127.0.01", 5656);
            NetworkStream clientStream = client.GetStream();
            StreamReader sr = new StreamReader(clientStream);
            StreamWriter sw = new StreamWriter(clientStream);
            sw.AutoFlush = true;
                //CLOSING SOCKET
                clientStream.Close();
                client.Close();
                Console.ReadLine();


    }
}

我的服务器代码：

sereve.cs

class Server
{
    public static void ServerCode(object port)

    {

        //SOCKET CONNECTION

        int Port = (int)port;
        Console.WriteLine("................SERVER RUNNING......................");
        TcpListener listener = new TcpListener(IPAddress.Parse("127.0.0.1"), Port);
        listener.Start();
        while (true)
        {
            TcpClient serverSite = listener.AcceptTcpClient();
            if (serverSite.Connected)
            {
                Thread c = new Thread((fileTransfer));
                c.Start(serverSite);
            }
        }
    }

    public static void fileTransfer(object clients)
    {


            Console.WriteLine("new client");*/
            TcpClient server = listener.AcceptTcpClient();//(TcpClient)clients;
            NetworkStream serverStream = server.GetStream();
            StreamReader sr = new StreamReader(serverStream);
            StreamWriter sw = new StreamWriter(serverStream);
            sw.AutoFlush = true;



            //CHECKING USERNAME AND PASSWORD
            Console.WriteLine("Connecting to Client... ");
            string fromClient_u = sr.ReadLine();
            Console.WriteLine("\n  Username: " + fromClient_u);
            string fromClient_p = sr.ReadLine();
            Console.WriteLine("\n  Password: *******");
            if (fromClient_u == "Client1" && fromClient_p == "123456")
            {

                Console.WriteLine("\nClient has Successfully Loged In. ");
                sw.WriteLine("Connection Complete...  ");                       //msg1
                sw.WriteLine("Successfully Connected to the Server.");          //msg2
                sw.WriteLine("Enter Some Informations for File Transfer...");   //msg3

            }
            //CLOSING SOCKET
            serverStream.Close();
            server.Close();
            Console.ReadLine();

    }   

}

它不起作用。我希望第一个线程工作并结束，然后第二个线程开始。但是这段代码会同时生成所有三个威胁。我的观点是，这个代码将创建多个客户端，他们将等待。当第一个客户端完成与服务器一起工作时，第二个客户端将获得服务器连接。

Answer 1

如果不提供服务器代码，也很难知道问题是否也存在。如果有一个比较结帐有助于本文介绍如何create a quick client and server application。该示例还允许任意数量的客户端，但它们必须作为独立进程启动，而不是线程。

要一次只运行一个客户端，您可以尝试更改起始代码，如下所示：

    for (i = 0; i < 3; i++)
    {
        t[i].Start();
        t[i].Join();
    }

Answer 2

听起来很简单，如果你想锁定进程直到客户端结束然后启动下一个进程，只需循环并明确调用它：

for (i=0;i<3;i++)
{
    Client.ClientCode();
}

如何在一台服务器上创建多个客户端？

2 个答案: