PHP选项组

Question

我有一个用PHP构建的选项组。一切都很好，直到我必须得到DetailID的值而不是DetailName来查找记录。我仍然需要显示DetailName而不是DetailID，我需要将DetailID添加到此。我该怎么做？

<?php
include("config.php");
$sql = "SELECT DetailType AS type, DetailID, GROUP_CONCAT(DISTINCT DetailName
          ORDER BY DetailName ASC   
          SEPARATOR '|') AS DetailName FROM tblDetails GROUP BY DetailType"; 
$result = mysql_query($sql) or die(mysql_error());  

while ($row = mysql_fetch_assoc($result)) { 
    echo "<optgroup label='{$row['type']}'>"; 
    $DetailNames = explode('|', $row['DetailName']); 
    foreach($DetailNames as $DetailName) { 
        echo '<option value='.$DetailID.'>'.$DetailName.'</option>';
    } 
    echo "</optgroup>";
}  
?>

表。 tblLocDet 位置ID 1,1,2,3 DetailID 1,2,3,4

tblDetails DetailType特征，膳食期，服务，类型 DetailID 1,2,3,4 DetailName自助餐，壁炉，WiFi，海滨

Answer 1

这有效......

$sql = "SELECT DISTINCT DetailType AS type, DetailID, DetailName FROM tblDetails
            ORDER BY DetailType, DetailName";
                     $result = mysql_query($sql) or die(mysql_error());
                     $prev='';
                     while ($row = mysql_fetch_assoc($result)) { 
                     if ($prev != $row['type']) {
                         if ($prev) echo "</optgroup>";
                         echo "<optgroup label='{$row['type']}'>";
                         $prev = $row['type'];
                         }
                         echo "<option value='".$row['DetailID']."'>".$row['DetailName']."</option>";                            }
                         echo "</optgroup>";