Question

我有一个套接字服务器，它一直在监听传入的请求。收到的数据将采用二进制字节数组的形式。数据格式是这样的。的 2321902321221200AA

而 1 字节是数据开始
4 位是版本
4 位是数据返回类型
5 字节是产品代码
2 字节数据长度

问题是，如何解析数据并隔离参数。

提前致谢!!

Answer 1

尝试java.io.DataInputStream：

    DataInputStream dis = new DataInputStream(in);
    byte b = dis.readByte();
    int version = (b >> 4) & 0xF;
    int returnType = b & 0xF;
    byte[] productCode = new byte[5];
    dis.readFully(productCode);
    int len = dis.readShort() & 0xFFFF;

Answer 2

如果使用java binary block parser，则代码将显示为

class Parsed { 
  @Bin byte begin; 
  @Bin(type = BinType.BIT) int version; 
  @Bin(type = BinType.BIT) int returnType;
  @Bin byte [] productCode;
  @Bin(type = BinType.USHORT) int dataLength;
}
final Parsed parsed = JBBPParser.prepare("byte begin; bit:4 version; bit:4 returnType; byte [5] productCode; ushort dataLength;")
        .parse(new byte[]{0x23,0x21,(byte)0x90,0x23,0x21,0x22,0x12,0x00,(byte)0xAA})
        .mapTo(Parsed.class);

assertEquals(0x23, parsed.begin);
assertEquals(0x01, parsed.version);
assertEquals(0x02, parsed.returnType);
assertArrayEquals(new byte[]{(byte)0x90,0x23,0x21,0x22,0x12}, parsed.productCode);
assertEquals(0x00AA,parsed.dataLength);

Answer 3

try {
    char [] cbuf = new char[16];
    char databegin = cbuf[0];
    char [] version = Arrays.copyOfRange(cbuf, 1, 6) 
    char [] product_typep = Arrays.copyOfRange(cbuf, 7, 12)
    char []data_lendth = Arrays.copyOfRange(cbuf, 13, 15)

} catch(Error e){
    System.out.println(e);
}

Answer 4

byte [] data = receiveData ();

int dataBegin = data [0];           // Once field is 1-byte, it is simple!
int version = data [1] & 0x0F;      // Use shift (>>>) and binary "and" (&)
int returnCode =                    // to extract value of fields that are
    (data [1] >>> 4) & 0x0F;        // smaller than one byte
byte [] productCode =               // Copy fixed-size portions of data
    new byte [] {                   // into separate arrays using hardcode
        data [2], data [3],         // (as here),  or System.arrayCopy
        data [4], data [5],         // in case field occupies quite
        data [6]};                  // a many bytes.
int dataLength =                    // Use shift (<<) binary or (|) to 
    (data [7] & 0xFF) |             // Combine several bytes into one integer
    ((data [8] & 0xFF) << 8);       // We assume little-endian encoding here

Answer 5

我会得到一些包装读者之王：

class Record {

   .....

   Record static fromBytes(byte[] bytes) {
       // here use ByteBuffer or DataInputStream to extract filds
       ......
   }
}


Record readNextRecord(InputStream in) {
    int len = in.read() && 0xFF;
    byte[] data = new byte[len];
    in.read(data);
    return Record.fromBytes(data)
}



{
  InputStream in = ....;
  Record r readNextRecord(in);
  process (r);
}

当然，您需要添加错误处理。一般来说，对于应该运行可靠的东西，我建议使用像Grizzly或Netty这样的NIO框架。

Answer 6

您可以通过ByteArrayOutputStream获取数据然后通过应用掩码（主要是AND，OR）来解析字节。

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