Question

我在APCS，我必须扩展一个小动物类，让一个小动物随机选择网格中的任何一个演员，然后移动到它的位置;从而“跟随”它。我的老师给了我们开始的课程和方法名称，开头不能改变。这是一个无法改变的跑步者。

import java.awt.Color;

import info.gridworld.actor.Rock;
import info.gridworld.actor.Actor;
import info.gridworld.actor.Flower;
import info.gridworld.actor.Bug;
import info.gridworld.grid.Location;
import info.gridworld.grid.BoundedGrid;
import info.gridworld.actor.ActorWorld;

public class AnnoyingCritterRunner
{
 public static void main(String[] args)
 {
  ActorWorld world = new ActorWorld(new BoundedGrid<Actor>(8,8));
  world.add(new Location(1, 1), new AnnoyingCritter());
  world.add(new Location(3, 1), new Rock());
  world.add(new Location(5, 2), new Actor());
  world.add(new Location(7, 6), new Flower());
  world.add(new Location(6, 6), new Actor());
  world.add(new Location(0, 5), new Actor());
  world.add(new Location(2, 6), new Bug(Color.GREEN));
  world.add(new Location(3, 5), new Actor());
  world.show();
 }
}

AnnoyingCritter类必须包含生物找到“最好的朋友”和“跟随它”所需的所有方法。

import info.gridworld.actor.Actor;
import info.gridworld.actor.Critter;
import info.gridworld.grid.Location;
import java.awt.Color;

import java.util.ArrayList;

public class AnnoyingCritter extends Critter
{
 /* instance variables will be needed
  * one for the bFF and one to set whether this Critter has a bFF (a boolean)
  */

  public AnnoyingCritter()
  {
    /* make an AnnoyingCritter constructor that sets a color and starts with the 
  * boolean variable above being "false"
  */
    Critter AnnoyingCritter = new Critter();
    AnnoyingCritter.setColor(Color.green);

  }

  private void pickBFF()
 {
    /* you'll need the grid, occupied locations, and some randomness to pick a friend
    */

 }

 public void processActors( ArrayList<Actor> actors)
 {
   /* this can be simple or complicated.  the idea is to pick a BFF if 
    * one is needed
    */
  if( !hasFriend )
  {

  }
//and it eats flowers and rocks
  for( Actor dude : actors )
  {

  }
 }

 public Location selectMoveLocation( ArrayList<Location> locs )
 {
  //you need a Grid

   //you need a location

  //you need to know where to go and if it's clear to move and then go there

 }
}

AnnoyingCritter必须移动到它随机选择的演员的位置并吃掉挡路的花和石头。它还需要一次移动到演员一个空间的位置。我无法弄清楚如何让恼人的小动物找到演员的位置，然后随机找到一个。进口也不能改变。

请帮助，因为我被困在这几个小时。

Answer 1

我很确定你必须使用getLocation（）来查找actor的位置。或者......您可以使用循环并为列和行选择随机数，直到找到一个actor。拍，这听起来是个好主意。我打算试一试。

Answer 2

Location类有一些强大的方法。试试这个：

int direction=getLocation().getDirectionToward(BFF.getLocation);
moveTo(getLocation().getAdjacentLocation(direction));

这应该让你一次向BFF移动一个空间。

要找到BFF：

Grid<Actor> grid=getGrid();
ArrayList<Location> locList=grid.getOccupiedLocations();
BFF=grid.get(locList.get(0));

确保locList（0）不是你自己的生物。

尝试阅读“快速参考”指南。

AnnoyingCritter GridWorld案例研究

2 个答案: