我想要发生的是我想要将ID等于ParentID的元素放入其中?所以在我的例子中,ParentId = 1的Group应该在Id = 1的Group中,我怎么能这样做?太困惑了..
截至目前,这是我的代码:
XElement xroot = new XElement("Root");
XElement xnavigations = null;
XElement xmenus = null;
foreach (DataRow navigations in GetNavigationSets().Rows)
{
xnavigations = new XElement("Group",
new XElement("GroupName", navigations["name"].ToString())
);
xnavigations.SetAttributeValue("Id", navigations["id"].ToString());
xnavigations.SetAttributeValue("ParentId", navigations["parent_id"].ToString());
foreach (DataRow menus in GetMenusInNavigationSetByNavigation(int.Parse(navigations["id"].ToString())).Rows)
{
foreach (DataRow menu in GetMenuById(int.Parse(menus["menu_id"].ToString())).Rows)
{
xmenus = new XElement("Menu",
new XElement("Name", menu["name"].ToString()),
new XElement("Price", menu["price"].ToString()),
new XElement("Description", menu["description"].ToString())
);
xnavigations.Add(xmenus);
}
}
xroot.Add(xnavigations);
}
xroot.Save("main.xml");
新输出:
答案 0 :(得分:3)
这是变异方法,依赖于副作用。它不像递归和重建一样干净,但它通常“足够”。而且,写起来非常简单。
输入“XML”:
var root = XElement.Parse(@"<root>
<group id='1' />
<group id='4' parent='2' />
<group id='2' parent='1' />
<group id='3' parent='2' />
<group id='5' />
</root>");
变成树:
// So we can find parent by ID
var groupMap = root.Elements("group")
.ToDictionary(e => (string)e.Attribute("id"), e => e);
// ToList so we don't iterate modified collection
foreach (var e in root.Elements().ToList()) {
XElement parent;
if (groupMap.TryGetValue((string)e.Attribute("parent") ?? "", out parent)) {
// Unlike standard XML DOM,
// make sure to remove XElement from parent first
e.Remove();
// Add to correct parent
parent.Add(e);
}
}
// LINQPad :-)
// root.Dump();
输出XML:
<root>
<group id="1">
<group id="2" parent="1">
<group id="4" parent="2" />
<group id="3" parent="2" />
</group>
</group>
<group id="5" />
</root>