更新
似乎我从这个问题" AAAAAA"
复制字符串并替换它。该程序正常工作。
所以我只是通过将" AAAAAA"
更改为我之前的错误字符串来进行一些测试。
然后删除所有空格并通过键入手动输入它,它可以工作!?!?。
这是我的完整代码
public static void main(String[] args) {
URL url;
InputStream is = null;
try {
url = new URL(
"http://writer.dek-d.com/nattione/story/viewlongc.php?id=466201&chapter=966");
is = url.openStream(); // throws an IOException
String result = convertStreamToString(is);
createFictionFiles(result);
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} finally {
try {
is.close();
} catch (IOException e) {
// nothing to see here
}
}
}
public static void createFictionFiles(String html) {
Document doc = Jsoup.parse(html);
Element title = doc.select("title").first();
Element table = doc.select("#story_body").first();
String showTitle = "";
String showStory = "";
BufferedWriter bw;
try {
showTitle = new String(title.text());
showStory = new String(table.text());
//showStory = " AAAAAA"; these spaces I copy it from log in eclipse. It is the spaces that come from web
boolean find = showStory.contains("\\t");
boolean find1 = showStory.contains("\\n");
boolean find2 = showStory.contains("\\x0b");
boolean find3 = showStory.contains("\\r");
boolean find4 = showStory.contains("\\f");
boolean find5 = showStory.contains(" ");
boolean find6 = showStory.contains(" ");
boolean find7 = showStory.matches("\\s");
System.out.println("\\t = " + find);
System.out.println("\\n = " + find1);
System.out.println("\\x0b = " + find2);
System.out.println("\\r = " + find3);
System.out.println("\\f = " + find4);
System.out.println(" = " + find5);
System.out.println(" = " + find6);
System.out.println("\\s = " + find7);
File file = new File("D:/" + "test"
+ ".txt");
if (!file.exists()) {
file.createNewFile();
}
FileWriter fw = new FileWriter(file.getAbsoluteFile());
bw = new BufferedWriter(fw);
bw.write(showStory);
bw.close();
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
public static String convertStreamToString(InputStream is) {
Scanner s = new Scanner(is, "TIS-620").useDelimiter("\\A");
return s.hasNext() ? s.next() : "";
}
OLD
我有这个字符串
showStory = " AAAAAA";
从Web检索这些字符串,并使用library
将其解析为String格式我希望单独使用超过3的空格将其替换为"\n"
我有这些测试。
boolean find = showStory.contains("\\t");
boolean find1 = showStory.contains("\\n");
boolean find2 = showStory.contains("\\x0b");
boolean find3 = showStory.contains("\\r");
boolean find4 = showStory.contains("\\f");
boolean find5 = showStory.contains(" ");
boolean find6 = showStory.contains(" ");
boolean find7 = showStory.contains("\\s");
,结果是
\t = false
\n = false
\x0b = false
\r = false
\f = false
= true
= false
\s = false
我不知道为什么不止一个空格给我假,即使在我的String中有8个空格。
我还将方法从contains
更改为matches
,但所有结果都是错误的。
任何人都可以帮我吗?
感谢。
答案 0 :(得分:3)
请再次检查......它无法识别find6中的2个空格
String showStory = " AAAAAA";
boolean find = showStory.contains("\\t");
boolean find1 = showStory.contains("\\n");
boolean find2 = showStory.contains("\\x0b");
boolean find3 = showStory.contains("\\r");
boolean find4 = showStory.contains("\\f");
boolean find5 = showStory.contains(" ");
boolean find6 = showStory.contains(" ");
boolean find7 = showStory.contains("\\s");
System.out.println("find ="+find);
System.out.println("find1 ="+find1);
System.out.println("find2 ="+find2);
System.out.println("find3 ="+find3);
System.out.println("find4 ="+find4);
System.out.println("find5 ="+find5);
System.out.println("find6 ="+find6);
System.out.println("find7 ="+find7);
}//end of main
这是印刷品:
find =false
find1 =false
find2 =false
find3 =false
find4 =false
find5 =true
find6 =true
find7 =false