关于PHP声明

Question

任何人都可以帮助我为此声明制作代码

<?php if(get_post_meta($post->ID, "price", $single = true) != ""){ ?>
<?php echo get_post_meta($post->ID, "price",$single = true); ?>
<?php } ?>

如果在我的自定义字段中为空，我希望语句继续使用此代码

<?php $asin = get_post_meta($post->ID, 'asin', true);
echo azon_us_price($asin);
 ?>

Answer 1

我想你想这样做：

<?php
if(!empty(get_post_meta($post->ID, "price", $single = true))){ 
  echo get_post_meta($post->ID, "price",$single = true); 
} else {
  $asin = get_post_meta($post->ID, 'asin', true);
  echo azon_us_price($asin);
}
?>