Question

我将源代码复制并粘贴到我的代码中，然后将tetrominoes数组扩展为包含5个以上的形状。它们被正确绘制，但DrawNext函数存在容纳它们的问题。编写函数的最佳方法是什么，因此它将使用扩展数组？

我的代码：

private function DrawNext():void {
    if (getChildByName("next")!=null) {
        removeChild(getChildByName("next"));
    }
    var next_t:Sprite=new Sprite();
    next_t.x=352;
    next_t.name="next";
    addChild(next_t);
    next_t.graphics.lineStyle(0,0xFFFFFF);
    //The problem is here! Everything in the Output windows points to either it or this method
    //i and j check to see if a piece in the grid is empty (0) or full (1).
    for (var i:int=0; i<tetrominoes[nextTetromino][0].length; i++) {
        for (var j:int=0; j<tetrominoes[nextTetromino][0][i].length; j++) {
                //When it encounters a 1, it draws a new sprite of a particular color
                //The color is determined by the piece that is being drawn.
            if (tetrominoes[nextTetromino][0][i][j]==1) {
                next_t.graphics.beginFill(colors[nextTetromino]);
                next_t.graphics.drawRect(tileSize*j,tileSize*i,tileSize,tileSize);
                next_t.graphics.endFill();
            }
        }
    }
}
private function BuildTetrominoes():void {
    // I
    tetrominoes[0]=[[[0,0,0,0],[1,1,1,1],[0,0,0,0],[0,0,0,0]],
        [[0,1,0,0],[0,1,0,0],[0,1,0,0],[0,1,0,0]]];
    colors[0]=0x00FFFF; //Cyan
    // T
    tetrominoes[1]=[[[0,0,0,0],[1,1,1,0],[0,1,0,0],[0,0,0,0]],
         [[0,1,0,0],[1,1,0,0],[0,1,0,0],[0,0,0,0]],
         [[0,1,0,0],[1,1,1,0],[0,0,0,0],[0,0,0,0]],
         [[0,1,0,0],[0,1,1,0],[0,1,0,0],[0,0,0,0]]];
    colors[1]=0xAA00FF; //Purple
    // L
    tetrominoes[2]=[[[0,0,0,0],[1,1,1,0],[1,0,0,0],[0,0,0,0]],
         [[1,1,0,0],[0,1,0,0],[0,1,0,0],[0,0,0,0]],
         [[0,0,1,0],[1,1,1,0],[0,0,0,0],[0,0,0,0]],
         [[0,1,0,0],[0,1,0,0],[0,1,1,0],[0,0,0,0]]];
    colors[2]=0xFFA500; //Orange
    // J
    tetrominoes[3]=[[[1,0,0,0],[1,1,1,0],[0,0,0,0],[0,0,0,0]],
         [[0,1,1,0],[0,1,0,0],[0,1,0,0],[0,0,0,0]],
         [[0,0,0,0],[1,1,1,0],[0,0,1,0],[0,0,0,0]],
         [[0,1,0,0],[0,1,0,0],[1,1,0,0],[0,0,0,0]]];
    colors[3]=0x0000FF; //Blue
    // Z
    tetrominoes[4]=[[[0,0,0,0],[1,1,0,0],[0,1,1,0],[0,0,0,0]],
         [[0,0,1,0],[0,1,1,0],[0,1,0,0],[0,0,0,0]]];
    colors[4]=0xFF0000; //Red
    // S
    tetrominoes[5]=[[[0,0,0,0],[0,1,1,0],[1,1,0,0],[0,0,0,0]],
         [[0,1,0,0],[0,1,1,0],[0,0,1,0],[0,0,0,0]]];
    colors[5]=0x00FF00; //Green
    // O
    tetrominoes[6]=[[[0,1,1,0],[0,1,1,0],[0,0,0,0],[0,0,0,0]]];
    colors[6]=0xFFFF00; //Yellow
    //X
    tetrominoes[7] = [[[0,1,0,0],[1,1,1,0],[0,1,0,0],[0,0,0,0]]];
    colors[7] = 0x00FF80;
    //U
    tetrominoes[8] = [[[1,1,1,0],[1,0,1,0],[0,0,0,0],[0,0,0,0]],
        [[1,1,0,0],[1,0,0,0],[1,1,0,0],[0,0,0,0]],
        [[1,0,1,0],[1,1,1,0],[0,0,0,0],[0,0,0,0]],
        [[0,0,1,1],[0,0,0,1],[0,0,1,1],[0,0,0,0]]];
    colors[8] = 0xFF007F;
    //V
    tetrominoes[9] = [[[1,1,0,0],[1,0,0,0],[0,0,0,0],[0,0,0,0]],
        [[0,0,1,1],[0,0,0,1],[0,0,0,0],[0,0,0,0]],
        [[0,0,0,0],[0,0,0,0],[0,0,0,1],[0,0,1,1]],
        [[0,0,0,0],[0,0,0,0],[1,0,0,0],[1,1,0,0]]];
    colors[9] = 0xFF00FF;
    //Colon
    tetrominoes[10] = [[[1,1,0,0],[0,0,0,0],[0,0,0,0],[0,0,0,0]]
        [[1,0,0,0],[1,0,0,0],[0,0,0,0],[0,0,0,0]]];
    colors[10] = 0x0080FF;
    //Dot
    tetrominoes[11] = [[[1,0,0,0],[0,0,0,0],[0,0,0,0],[0,0,0,0]]];
    colors[11] = 0xFF4000;
}

源代码几乎相同，但BuildTetrominoes（）函数中的形状7-11除外。

如何修改绘图功能以适应扩展的形状阵列？

0 个答案: