Question

我正在尝试在iOS UIwebview上禁用超链接和复制/粘贴菜单所以我用Google搜索，有很多答案。然后我遇到另一个问题'webviewdidfinishload not called' 所以我添加我的代码来征求你的帮助。（我确定我正确连接了IBOutlet）

另外，我仍然没有想到把mainWebView.delegate = self而不是self.mainWebView.delegate = self 有人可以解释这个区别吗？所以我不确定我的其他功能是什么 [[[mainWebView subviews] lastObject] setScrollEnabled：YES] [[[mainWebView subviews] lastObject] setScrollsToTop：NO]
mainWebView.scalesPageToFit = YES 这些是否有效。

它应该在ios5到ios6.1上工作谢谢

<。>文件中的

@interface HRViewController : UIViewController <UIWebViewDelegate>
{
    UIWebView *mainWebView;
}
@property (strong, nonatomic) IBOutlet UIWebView *mainWebView;

@end

<。>文件中的

@interface HRViewController ()

@end

@implementation HRViewController

@synthesize mainWebView;

- (void)viewDidLoad
{
    [self startWebView];
    [super viewDidLoad];
}

- (void)startWebView
{
    mainWebView.delegate = self;

    [[[mainWebView subviews] lastObject] setScrollEnabled:YES];
    [[[mainWebView subviews] lastObject] setScrollsToTop:NO]; 
    mainWebView.scalesPageToFit = YES;

    mainWebView = [[UIWebView alloc] initWithFrame:self.view.bounds];
    mainWebView.scalesPageToFit = YES;
    [self.view addSubview:self.mainWebView];

    NSURL *url = [NSURL URLWithString:/" @"http://www.mysite.com" "/];
    NSURLRequest *request = [NSURLRequest requestWithURL:url];

    [mainWebView loadRequest:request];
}

- (void)webViewDidFinishLoad:(UIWebView *)WebView {
    NSLog(@"finish");

    [WebView stringByEvaluatingJavaScriptFromString: @"document.documentElement.style.webkitUserSelect='none';"];
    [WebView stringByEvaluatingJavaScriptFromString: @"document.documentElement.style.webkitTouchCallout='none';"];
}

- (void)webViewDidStartLoad:(UIWebView *)mainWebView {
    NSLog(@"start");
}

- (void)webView:(UIWebView *)webView didFailLoadWithError:(NSError *)error {
    NSLog(@"Error for WEBVIEW: %@", [error description]);
}

EDIED 我使用下面的代码，但仍然无法工作...... 这些都不起作用!!!!!

- (BOOL)canPerformAction:(SEL)action withSender:(id)sender
{
    NSLog(@"canPerformAction: %@",NSStringFromSelector(action));
    if (action == @selector(copy:) ||
        action == @selector(paste:)||
        action == @selector(cut:)) {
        return NO;
    }
    return NO;
}

和这个

- (BOOL)canPerformAction:(SEL)action withSender:(id)sender
{
    UIMenuController *menuController = [UIMenuController sharedMenuController];
    if (menuController) {
        [UIMenuController sharedMenuController].menuVisible = NO;
    }
    return NO;
}

甚至这个 - （void）viewDidLoad { mainWebView.delegate = self; }

- (void)webViewDidFinishLoad:(UIWebView *)webView {
    NSLog(@"finish");
    // Disable user selection
    [webView stringByEvaluatingJavaScriptFromString:@"document.documentElement.style.webkitUserSelect='none';"];
    // Disable callout
    [webView stringByEvaluatingJavaScriptFromString:@"document.documentElement.style.webkitTouchCallout='none';"];
}

也是这个 - （void）viewDidLoad { [self longPress：self.mainWebView]; }

- (void)longPress:(UIView *)webView {
    UILongPressGestureRecognizer* longPress = [[UILongPressGestureRecognizer alloc] initWithTarget:self action:@selector(handleLongPress)];

    longPress.allowableMovement=100;
    longPress.minimumPressDuration=0.3;
    longPress.delaysTouchesBegan=YES;
    longPress.cancelsTouchesInView=YES; 
    [webView addGestureRecognizer:longPress]; 
}

// I just need this for the selector in the gesture recognizer.
- (void)handleLongPress {

}

请帮助我..它让我疯狂了一个星期..

Answer 1

隐藏复制/粘贴菜单：

重写canPerformAction:withSender:方法以返回NO您不想允许的操作：

- (BOOL)canPerformAction:(SEL)action withSender:(id)sender
{
    if (action == @selector(paste:))
        return NO;

    if (action == @selector(select:))   
        return NO;

    if (action == @selector(selectAll:))   
        return NO;

    return [super canPerformAction:action withSender:sender];
}

另一种方式：

- (BOOL)canPerformAction:(SEL)action withSender:(id)sender
{
    UIMenuController *menuController = [UIMenuController sharedMenuController];
    if (menuController) {
        [UIMenuController sharedMenuController].menuVisible = NO;
    }
    return NO;
}

同时检查This link

要停用超链接：

您可以从this site获得此问题的答案。

关于UIWebView：

如果您使用ARC，则只写，

@property (strong, nonatomic) IBOutlet UIWebView *mainWebView;

无需@synthesize财产，其他方面，

@interface HRViewController : UIViewController <UIWebViewDelegate>
{
    UIWebView *mainWebView;
}

@property (nonatomic,retain) IBOutlet UIWebView *mainWebView;

@end

// .m file

- (void)viewDidLoad
{
    mainWebView = [[UIWebView alloc] initWithFrame:self.view.bounds];
    mainWebView.scalesPageToFit = YES;
    mainWebView.delegate = self;

    [[[mainWebView subviews] lastObject] setScrollEnabled:YES];
    [[[mainWebView subviews] lastObject] setScrollsToTop:NO];
    mainWebView.scalesPageToFit = YES;

    [self.view addSubview:self.mainWebView];

    NSURL *url = [NSURL URLWithString:@"http://www.mysite.com"];
    NSURLRequest *request = [NSURLRequest requestWithURL:url];
    [mainWebView loadRequest:request];
}

这可能对您有所帮助。

如何禁用iOS上的超链接和复制/粘贴菜单以及未调用的webviewdidfinishload

1 个答案: