我正在设计一个查看单词列表的程序,并计算有多少单词只包含字母p,y,t,h,o和n。
到目前为止,我的代码是:
def find_python(string, python):
"""searches for the letters 'python' in the word."""
for eachLetter in python:
if eachLetter not in string:
return False
return True
def main():
python = 'python'
how_many = 0
try:
fin = open('words.txt')#open the file
except:
print("No, no, file no here") #if file is not found
for eachLine in fin:
string = eachLine
find_python(string, python)
if find_python(string, python) == True:
how_many = how_many + 1#increment count if word found
print how_many#print out count
fin.close()#close the file
if __name__ == '__main__':
main()
但是,我的代码返回的单词数量不正确,例如,如果我输入print语句,它将返回单词'xylophonist',因为它中包含字母python。我应该怎么做才会拒绝任何禁止使用的字?
答案 0 :(得分:3)
更正您的测试功能:
def find_python(string, python):
"""searches for the letters 'python' in the word.
return True, if string contains only letters from python.
"""
for eachLetter in string:
if eachLetter not in python:
return False
return True
答案 1 :(得分:0)
from os import listdir
def diagy(letters,li):
return sum( any(c in letters for c in word) for word in li )
def main():
dir_search = 'the_dir_in_which\\to_find\\the_file\\'
filename = 'words.txt'
if filename in listdir(dir_search):
with open(dir_search + 'words.txt',) as f:
li = f.read().split()
for what in ('pythona','pyth','py','ame'):
print '%s %d' % (what, diagy(what,li))
else:
print("No, no, filename %r is not in %s" % (filename,dir_search))
if __name__ == '__main__':
main()
答案 2 :(得分:0)
欢迎来到正则表达式:
import re
line = "hello python said the xylophonist in the ythoonp"
words = re.findall(r'\b[python]+\b',line)
print words
返回
['python', 'ythoonp']
如果您想要查找实际单词python出现的次数,那么您应该发出re.findall(r'\bpython\b')
如果你不想走这条路线,如果字符串中的任何字母不是p,y,t,h,o或n,我建议你返回false。