android:从listview中删除项目无法正常工作

时间:2013-02-08 23:13:19

标签: android listview delete-row

我有两个textview和一个按钮的自定义适配器,应删除该行。

public class ListViewAdapter extends ArrayAdapter<OneRowListView> implements OnClickListener {
private ArrayList<OneRowListView> items;
private ContactsActivity ca;
private int position;
private OneRowListView o;

public ListViewAdapter(Context context, int textViewResourceId, ArrayList<OneRowListView> items) {
    super(context, textViewResourceId, items);
    this.items = items;
    ca = (ContactsActivity) context;
}   
@Override
public View getView(int pos, View convertView, ViewGroup parent) {
        View v = convertView;
        position = pos;
        if (v == null) {
            LayoutInflater vi = (LayoutInflater)ca.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
            v = vi.inflate(R.layout.one_item_contacts_list, null);
        }
        o = items.get(position);
        if (o != null) {
                TextView name = (TextView) v.findViewById(R.id.name);
                TextView surname = (TextView) v.findViewById(R.id.surname);
                TextView phoneNumber = (TextView) v.findViewById(R.id.phonenumber);
                Button deleteButton = (Button) v.findViewById(R.id.deleteButton);
                deleteButton.setOnClickListener(this);
        // ...
        }
        return v;
 }

@Override
public void onClick(View v) {
    switch(v.getId()){
    case R.id.deleteButton:
        remove(items.remove(position));
        notifyDataSetChanged();
        break;
    }       
}
 }

问题是,当按下任何按钮时,它总是删除最后一行,而不是当前行。可变位置始终指向最后一行。 问题在哪里?

1 个答案:

答案 0 :(得分:1)

问题是当你执行position = pos;时,你会继续覆盖'position'变量(因为在滚动ListView时,每行都会调用getView())。

作为快速修复,您可以在deleteButton包含行位置的标记中存储,而不是使用'position'变量。例如,在你的getView()方法中这样的东西:

deleteButton.setTag(pos);

然后在你的onClick()方法中你可以这样做:

int position = (int) v.getTag();
...