我有一个mpi程序,我正在尝试测量它的运行时间。所以我添加了2次调用gettimeofday,这就是一切都停止工作的地方。出于某种原因,如果我在那里第二次调用gettimeofday,它只会崩溃。这是我得到的信息:
MPI应用程序等级0在具有信号11的MPI_Finalize()之前被杀死 srun:错误:n32:task0:退出退出代码245
这是代码
struct timeval starttime;
struct timeval endtime;
gettimeofday(&starttime, NULL);
int numDarts = 1000000000;
int numWorkers = 2;
char* args[1];
if(argc >= 2)
{
numWorkers = atoi(argv[1]);
}
if(argc >= 3)
numDarts = atoi(argv[2]);
MPI_Init(&argc, &argv);
MPI_Comm_size(MPI_COMM_WORLD, &world_size);
printf("world size = %i\n", world_size);
if (world_size != 1)
printf("Top heavy with management\n");
int numDartsWorker = numDarts/numWorkers;
int numDartsMaster = numDarts/numWorkers + (numDarts % numWorkers); //the master computes the leftover
args[0] = malloc(256 * sizeof(char));
sprintf(args[0], "%i", numDartsWorker);
// printf("argument passing to workers: %s\n", args[0]);
/*
* Now spawn the workers. Note that there is a run-time determination
* of what type of worker to spawn, and presumably this calculation must
* be done at run time and cannot be calculated before starting
* the program. If everything is known when the application is
* first started, it is generally better to start them all at once
* in a single MPI_COMM_WORLD.
*/
// printf("About to call MPI_Comm_spawn with %i workers...\n", numWorkers);
int resultLen = 0;
//the master counts as a worker, hence the -1
MPI_Comm_spawn("piworker", args, numWorkers-1, MPI_INFO_NULL, 0, MPI_COMM_SELF,
&everyone, MPI_ERRCODES_IGNORE);
double pisum = 0;
double myresult = dboard(numDartsMaster);
printf("parent result is %.9f\n", myresult);
int rc = MPI_Reduce(&myresult, &pisum, 1, MPI_DOUBLE, MPI_SUM, MPI_ROOT, everyone);
if (rc != MPI_SUCCESS)
printf("failure on mpi_reduce\n");
free(args[0]);
/*
* Parallel code here. The communicator "everyone" can be used
* to communicate with the spawned processes, which have ranks 0,..
* MPI_UNIVERSE_SIZE-1 in the remote group of the intercommunicator
* "everyone".
*/
//receive the results
int i=1;
MPI_Status status;
double avgpi = pisum;
avgpi += myresult; //include master's average in the result.
avgpi /= numWorkers;
printf("startTime = %d secs, %d microsecs\n", starttime.tv_sec);
// gettimeofday(&endtime, NULL);
// double totalTime = ((double)endtime.tv_sec + (double)endtime.tv_usec/1000000.0f) -
// ((double)starttime.tv_usec + (double)starttime.tv_usec/1000000.0f);
// printf("Total time: %.8f\n", totalTime);
printf("With %i workers, %i darts, estimated value of pi is: %.9f\n", numWorkers, numDarts, avgpi);
MPI_Finalize();
return 0;
}
我在第二次调用gettimeofday之前输入了一个printf调用。如果第二个呼叫被注释掉,它只打印任何东西,否则它会崩溃。我在这个例子中注释了gettimeofday,但那是导致mpi崩溃的调用。如果我取消注释它,它会再次因我提到的错误消息而崩溃。
我想知道是否有人有任何见解,为什么gettimeofday会这样做。
答案 0 :(得分:1)
在你的代码中,有一个线程产生,如
//the master counts as a worker, hence the -1
MPI_Comm_spawn("piworker", args, numWorkers-1, MPI_INFO_NULL, 0, MPI_COMM_SELF,
&everyone, MPI_ERRCODES_IGNORE);
随后args被释放,如
free(args[0]);
这是预期的吗?这种记忆的释放不会影响个别线程吗?
答案 1 :(得分:0)
感谢nos,我评论了我的问题,我找到了解决方案。我摆脱了对sprintf的调用,sprintf被用来写入MPI_Comm_Spawn调用的参数字符串,该调用告诉工人要使用多少“飞镖”。相反,我使用MPI_Send向他们发送信息。似乎在我调用gettimeofday之前,sprintf不是一个问题。