Question

我正在尝试使用此范围执行此操作：

>> Job.last.application_date
  Job Load (0.4ms)  SELECT "jobs".* FROM "jobs" ORDER BY created_at ASC LIMIT 1
=> Wed, 13 Feb 2013
>> Date.today + 5.days
=> Wed, 13 Feb 2013
>> Job.where(application_date: Date.today + 5.days)
  Job Load (0.2ms)  SELECT "jobs".* FROM "jobs" WHERE "jobs"."application_date" = '2013-02-13' ORDER BY created_at DESC
=> []

更新

嗯，那不行，可能是因为有些数据格式。

>> Job.where("application_date = ?", Date.today + 5)
Job Load (0.3ms) SELECT "jobs".* FROM "jobs" WHERE (application_date = '2013-02-13') ORDER BY created_at DESC => [] 
>> Job.last.application_date Job Load (0.7ms)
 SELECT "jobs".* FROM "jobs" ORDER BY created_at ASC LIMIT 1 => Wed, 13 Feb 2013

# Schema jobs
#  application_date       :date

Answer 1

您可以使用：

where("application_date = ?", Date.today + 5)

如何从今天起5天后捕获所有对象？

1 个答案: