我已经使用了几个星期，似乎无法弄清楚如何用多条路径绘制下面的图表。 Focus+Context via Brushing chart
我试图创建一个jsfiddle，但无法复制我得到的屏幕。在这一点上，我所拥有的与原始图表类似，只有一条路径而不是区域和刷子工作。基本上尝试将焦点图表和多系列折线图Multiseries chart结合起来。
然而，当我尝试添加另一条路径时，没有任何作用。请提出我需要做出的任何想法或更改。还有我可以看到的任何其他类似的图表（或图表exaples）。可以以任何方式或形式重新排列数据以使其工作。
<div id='dashboardChart'>
<svg xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink"
id="svg">
</div>
path {
fill:none;
stroke:white;
stroke-width:2px;
}
.axis path, .axis line {
fill: none;
stroke: #CCC;
shape-rendering: crispEdges;
}
.brush .extent {
stroke: #fff;
fill-opacity: .125;
shape-rendering: crispEdges;
}
.path_green {
stroke:green;
}
.path_red {
stroke:red;
}
.path_yellow {
stroke:yellow;
}
function drawChart() {
var margin = {
top: 5,
right: 10,
bottom: 100,
left: 50
},
margin2 = {
top: 200,
right: 10,
bottom: 20,
left: 50
},
width = 1075 - margin.left - margin.right,
height = 280 - margin.top - margin.bottom,
height2 = 280 - margin2.top - margin2.bottom;
var parseDate = d3.time.format("%Y-%m-%d").parse;
var x = d3.time.scale().range([0, width]),
x2 = d3.time.scale().range([0, width]),
y = d3.scale.linear().range([height, 0]),
y2 = d3.scale.linear().range([height2, 0]);
var xAxis = d3.svg.axis().scale(x).orient("bottom"),
xAxis2 = d3.svg.axis().scale(x2).orient("bottom"),
yAxis = d3.svg.axis().scale(y).orient("left");
var brush = d3.svg.brush()
.x(x2)
.on("brush", brush);
var area = d3.svg.area()
.interpolate("monotone")
.x(function (d) {
return x(d.date);
})
.y0(height)
.y1(function (d) {
return y(d.red);
});
var area2 = d3.svg.area()
.interpolate("monotone")
.x(function (d) {
return x2(d.date);
})
.y0(height2)
.y1(function (d) {
return y2(d.red);
});
var svg = d3.select("#dashboardChart #svg")
.attr("width", width + margin.left + margin.right)
.attr("height", height + margin.top + margin.bottom);
svg.append("defs").append("clipPath")
.attr("id", "clip")
.append("rect")
.attr("width", width)
.attr("height", height);
var focus = svg.append("g")
.attr("transform", "translate(" + margin.left + "," + margin.top + ")");
var context = svg.append("g")
.attr("transform", "translate(" + margin2.left + "," + margin2.top + ")");
var data = [{
"date": "2013-02-08T05:00:00.000Z",
"data": null,
"red": 0,
"yellow": 0,
"green": 1
}, {
"date": "2013-02-07T05:00:00.000Z",
"data": null,
"red": 485,
"yellow": 0,
"green": 491
}, {
"date": "2013-02-06T05:00:00.000Z",
"data": null,
"red": 2884,
"yellow": 0,
"green": 2881
}, {
"date": "2013-02-05T05:00:00.000Z",
"data": null,
"red": 3191,
"yellow": 0,
"green": 3188
}, {
"date": "2013-02-04T05:00:00.000Z",
"data": null,
"red": 180,
"yellow": 0,
"green": 184
}, {
"date": "2013-02-03T05:00:00.000Z",
"data": null,
"red": 0,
"yellow": 0,
"green": 0
}, {
"date": "2013-02-02T05:00:00.000Z",
"data": null,
"red": 0,
"yellow": 0,
"green": 0
}, {
"date": "2013-02-01T05:00:00.000Z",
"data": null,
"red": 0,
"yellow": 0,
"green": 0
}, {
"date": "2013-01-31T05:00:00.000Z",
"data": null,
"red": 0,
"yellow": 0,
"green": 0
}, {
"date": "2013-01-30T05:00:00.000Z",
"data": null,
"red": 1,
"yellow": 0,
"green": 0
}, {
"date": "2013-01-29T05:00:00.000Z",
"data": null,
"red": 0,
"yellow": 0,
"green": 2
}, {
"date": "2013-01-28T05:00:00.000Z",
"data": null,
"red": 0,
"yellow": 0,
"green": 0
}, {
"date": "2013-01-27T05:00:00.000Z",
"data": null,
"red": 1,
"yellow": 1,
"green": 1
}, {
"date": "2013-01-26T05:00:00.000Z",
"data": null,
"red": 0,
"yellow": 0,
"green": 1
}, {
"date": "2013-01-25T05:00:00.000Z",
"data": null,
"red": 0,
"yellow": 0,
"green": 0
}, {
"date": "2013-01-24T05:00:00.000Z",
"data": null,
"red": 0,
"yellow": 0,
"green": 0
}, {
"date": "2013-01-23T05:00:00.000Z",
"data": null,
"red": 49,
"yellow": 0,
"green": 45
}, {
"date": "2013-01-22T05:00:00.000Z",
"data": null,
"red": 59,
"yellow": 0,
"green": 64
}, {
"date": "2013-01-21T05:00:00.000Z",
"data": null,
"red": 119,
"yellow": 1,
"green": 125
}, {
"date": "2013-01-20T05:00:00.000Z",
"data": null,
"red": 0,
"yellow": 1,
"green": 0
}, {
"date": "2013-01-19T05:00:00.000Z",
"data": null,
"red": 0,
"yellow": 0,
"green": 0
}, {
"date": "2013-01-18T05:00:00.000Z",
"data": null,
"red": 84,
"yellow": 0,
"green": 81
}, {
"date": "2013-01-17T05:00:00.000Z",
"data": null,
"red": 76,
"yellow": 1,
"green": 77
}, {
"date": "2013-01-16T05:00:00.000Z",
"data": null,
"red": 0,
"yellow": 1,
"green": 0
}, {
"date": "2013-01-15T05:00:00.000Z",
"data": null,
"red": 0,
"yellow": 0,
"green": 0
}, {
"date": "2013-01-14T05:00:00.000Z",
"data": null,
"red": 0,
"yellow": 0,
"green": 0
}, {
"date": "2013-01-13T05:00:00.000Z",
"data": null,
"red": 0,
"yellow": 0,
"green": 0
}, {
"date": "2013-01-12T05:00:00.000Z",
"data": null,
"red": 0,
"yellow": 0,
"green": 0
}, {
"date": "2013-01-11T05:00:00.000Z",
"data": null,
"red": 0,
"yellow": 0,
"green": 0
}, {
"date": "2013-01-10T05:00:00.000Z",
"data": null,
"red": 0,
"yellow": 0,
"green": 0
}];
x.domain(d3.extent(data.map(function (d) {
return d.date;
})));
y.domain([0, d3.max(data.map(function (d) {
return d.red;
}))]);
x2.domain(x.domain());
y2.domain(y.domain());
focus.append("path")
.datum(data)
.attr("clip-path", "url(#clip)")
.attr("d", area)
.attr("class", "path_red");
focus.append("g")
.attr("class", "x axis")
.attr("transform", "translate(0," + height + ")")
.call(xAxis);
focus.append("g")
.attr("class", "y axis")
.call(yAxis);
context.append("path")
.datum(data)
.attr("d", area2)
.attr("class", "path_red");
context.append("g")
.attr("class", "x axis")
.attr("transform", "translate(0," + height2 + ")")
.call(xAxis2);
context.append("g")
.attr("class", "x brush")
.call(brush)
.selectAll("rect")
.attr("y", -6)
.attr("height", height2 + 7);
function brush() {
x.domain(brush.empty() ? x2.domain() : brush.extent());
focus.select("path").attr("d", area);
focus.select(".x.axis").call(xAxis);
}
}
drawChart();
答案 0 :(得分：10)
根据您的评论，您可以绘制三个区域，但很难刷牙它们。我在这里有一个工作示例：http://jsfiddle.net/BVzyq/1/其中，我在数据中添加了三个与{em>颜色相对应的<path>元素：['red', 'yellow', 'green']。
我抽象出了可以采用颜色并返回相应d值的函数：
var area = function (color) {
return d3.svg.area()
.interpolate("monotone")
.x(function (d) {
return x(d.date);
})
.y0(height)
.y1(function (d) {
return y(d[color]);
});
};
var area2 = function (color) {
return d3.svg.area()
.interpolate("monotone")
.x(function (d) {
return x2(d.date);
})
.y0(height2)
.y1(function (d) {
return y2(d[color]);
});
};
它们可以进一步抽象，但它们最接近您编写的代码。 创建路径时使用这些函数：
focus.selectAll('path')
.data(['red', 'yellow', 'green'])
.enter()
.append('path')
.attr('clip-path', 'url(#clip)')
.attr('d', function (col) {
return area(col)(data);
})
.attr('class', function (col) {
return "path_" + col + " data";
});
// ...
context.selectAll('path')
.data(['red', 'yellow', 'green'])
.enter()
.append('path')
.attr('d', function (col) {
return area2(col)(data);
})
.attr('class', function (col) {
return "path_" + col;
});
CSS类似乎暗示了这种形式的数据连接。我还在与时间序列图对应的路径中添加了另一个类data。这样可以很容易地将这些<path>与用于轴的d区分开来。
最后，在画笔功能中，重新计算所有path.data元素的function brush() {
x.domain(brush.empty() ? x2.domain() : brush.extent());
focus.selectAll("path.data").attr("d", function (col) {
return area(col)(data);
});
focus.select(".x.axis").call(xAxis);
}
属性：
data请注意，我更改了{{1}}中的一些值，以使所有三种颜色都可见。
答案 1 :(得分：2)
伟大的解决方案musically_ut，对于其他有类似问题的人。我能够加载额外的csv，就像在这个链接中找到的例子一样 - Focus+Context via Brushing但是真的挂了如何将所有线条刷在一起，即使它们在区域和区域2中都正确渲染。
原来，看着你的代码，我所要做的就是改变focus.select to focus.select就像你一样。谢谢！
对于使用原始教程代码的任何人，只需复制以下代码并指向新的csv即可添加备用csv：
d3.csv("sp501.csv", function(error, data) {
data.forEach(function(d) {
d.date = parseDate(d.date);
d.price = +d.price;
});
x.domain(d3.extent(data.map(function(d) { return d.date; })));
y.domain([0, d3.max(data.map(function(d) { return d.price; }))]);
x2.domain(x.domain());
y2.domain(y.domain());
focus.append("path")
.datum(data)
.attr("clip-path", "url(#clip)")
.attr("d", area)
.attr("class", "timeLine2");
context.append("path")
.datum(data)
.attr("class", "timeLine2")
.attr("d", area2);
context.append("g")
.attr("class", "x axis2")
.attr("transform", "translate(0," + height2 + ")")
.call(xAxis2);
context.append("g")
.attr("class", "x brush")
.call(brush)
.selectAll("rect")
.attr("y", -6)
.attr("height", height2 + 7);
});