Question

我想要实现的是使用Backbone.Model或其他方法扩展先前定义的类，无论哪种方法效果最好。基本上我的代码看起来像这样：

var SomeObject = function() {};
SomeObject.CLASS_ATTRIBUTE = 'something';
SomeObject.prototype.aFunction = function() { return Math.E; };
SomeObject.prototype.attrB = 'wat';

var SomeModel = Backbone.Model.extend({});

此时，如何使用SomeModel（或相反的方式）扩展SomeObject以包含CLASS_ATTRIBUTE以及aFunction和attrB作为Model属性而不失去Backbone.Model能力？

感谢您的回答！

Answer 1

如果SomeObject被定义为：

var SomeObject = {
  CLASS_ATTRIBUTE: 'something',
  aFunction: function () { return MATH.E; },
  attrB: 'wat'
}

然后

var SomeModel = Backbone.Model.extend({
 // ...
});

_.extend(SomeModel.prototype, SomeObject);

会做你需要的东西

Answer 2

延伸是什么意思？

您想合并您的物品吗？
您是否希望向SomeModel添加自定义“方法”？
您是否希望创建一个同时包含SomeModel和SomeObject的方法和属性的新对象？

JSFiddle

var SomeObject = function() {};
SomeObject.CLASS_ATTRIBUTE = 'something';
SomeObject.prototype.aFunction = function() { return Math.E; };
SomeObject.prototype.attrB = 'wat';
var SomeModel = Backbone.Model.extend({});

// Merging instances of objects
var newSomeObject = new SomeObject(),
    newSomeModel = new SomeModel(),
    mergedObjects = $.extend(true, newSomeModel, newSomeModel);

console.log(mergedObjects);

// Prototyping
var mergedProto = $.extend(true, SomeModel.prototype, SomeObject.prototype);
console.log(mergedProto);

//factory
var myMergefactory = function() {
    var ret = $.extend(true, SomeModel.prototype, SomeObject.prototype);
    return ret;
}

作为一个说明，这也是有效的......

var SomeModel = Backbone.Model.extend({});
SomeModel.CLASS_ATTRIBUTE = 'something';
SomeModel.prototype.aFunction = function() { return Math.E; };
SomeModel.prototype.attrB = 'wat';

或者这......

var SomeModel = Backbone.Model.extend({
    initialize: function (params) {
        $.extend(true, this, params.obj);
    }
});
var mObj = new SomeModel({obj: new SomeObject()});

从/与其他非Backbone对象扩展Backbone.Model

2 个答案: