我有这个:
string strings = "a b c d d e";
我需要类似string.Contains()
的内容,但我不仅要知道字符串是否存在(如果是字母以上),还要如果是目前只有一个单一时间。
我怎样才能做到这一点?
答案 0 :(得分:14)
您可以使用LastIndexOf(String)
和IndexOf(String)
并验证返回的值是否相等。当然还要检查是否找到了String(即返回的值不是-1)。
答案 1 :(得分:5)
您可以使用LINQ
int count = strings.Count(f => f == 'd');
答案 2 :(得分:1)
替代
if(Regex.Matches(input,Regex.Escape(pattern)).Count==1)
答案 3 :(得分:0)
尝试如下......它会帮助你......
string strings = "a b c d d e";
string text ="a";
int count = 0;
int i = 0;
while ((i = strings.IndexOf(text, i)) != -1)
{
i += text.Length;
count++;
}
if(count == 0)
Console.WriteLine("String not Present");
if(count == 1)
Console.WriteLine("String Occured Only one time");
if(Count>1)
Console.WriteLine("String Occurance : " + count.Tostring());
答案 4 :(得分:0)
string source = "a b c d d e";
string search = "d";
int i = source.IndexOf(search, 0);
int j = source.IndexOf(search, i + search.Length);
if (i == -1)
Console.WriteLine("No match");
else if (j == -1)
Console.WriteLine("One match");
else
Console.WriteLine("More match");
答案 5 :(得分:0)
另一个简单的选择:
Original string: ./dir1/dir2/dir3
Its parent directories:
./dir1
./dir1/dir2
./dir1/dir2/dir3
Next one if exists...
Original string: ./dir4/dir5
Its parent directories:
./dir4
./dir4/dir5
Next one if exists...