<?php
// This block grabs the whole list for viewing
include "storescripts/connect_to_mysql.php";
$cat=$_POST['cat'];
$sql = mysql_query("select * from categories,products_cat,products where categories.id=products_cat.cat_id and products.id=products_cat.prod_id and categories=$cat");
$catCount = mysql_num_rows($sql); // count the output amount
while($row = mysql_fetch_array($sql)){
$id = $row["id"];
$product_name = $row["product_name"];
$price = $row["price"];
$date_added = strftime("%b %d, %Y", strtotime($row["date_added"]));
$prod_list .= "category ID: $id - <strong>$product_name</strong> <br />";
}
?>
我有这三个表: 1)产品表: id,product_name,price,category,subcategory
2)类别表: ID,猫
3)products_cat表: cat_id,prod_id
我无法显示某些类别的产品,用户将从命令行输入cat = x,它只会给我这个错误:
Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in /home/perzul12/public_html/beta/show.php on line 6
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /home/perzul12/public_html/beta/show.php on line 7
请帮帮我!这是我本月唯一的资金来源,我无法做到这一点!
答案 0 :(得分:0)
此处的工作不在弃用的mysql_
函数中。相反,您尚未返回有效的结果集。试试这个。
"select products_cat.products, categories.*
from categories,
left join products_cat on products_cat.cat_id=products.id
where categories={$cat}"