Question

如何将轮询线程传递给另一个线程进行处理。程序执行在一个控制器类中，它有一个main方法和一个线程池：

主类控制器

   public static void main(String[] args) throws InterruptedException {
    RunnableController controller = new RunnableController();

    System.out.println(incomingQueue.size());

    controller.initializeDb();
    controller.initialiseThreads();
    System.out.println("Polling");
    controller.initialUpdate(); 

}

具有轮询类

的线程的方法

 private void initialiseThreads()
{       
    try {

        threadExecutorRead = Executors.newFixedThreadPool(10);
PollingSynchronizer reader = new PollingSynchronizer(incomingQueue,dbConnection);   
        threadExecutorRead.submit(reader);

    }catch (Exception e){
        e.printStackTrace();
    }

}

具有proccesor类的线程的方法

    private void initialUpdate()
{
    RunnableController.outgoingQueue = incomingQueue;
    if((RunnableController.outgoingQueue)!= null){
        try {
            threadExecutorFetch = Executors.newFixedThreadPool(10);
        MessageProcessor updater = new MessageProcessor(outgoingQueue, dbConnection);
            threadExecutorFetch.submit(updater);
            DBhandler dbhandler = new DBhandler();
            dbhandler.updateDb(getOutgoingQueue());

        } catch (Exception e) {

        }
    }

}

Poller类和控制器类

    public void run() {// Thread in the Poller class 
    int seqId = 0;
    while(true) {
        List<KpiMessage> list = null;
        try {
            list = fullPoll(seqId);
            if (!list.isEmpty()) {
                seqId = list.get(0).getSequence();
                incomingQueue.addAll(list);
                this.outgoingQueue = incomingQueue;             
                System.out.println("waiting");
                System.out.println("new incoming message");
                while(true){
                        wait(3000);
                        notify();
                }
            }
        } catch (Exception e1) {
            e1.printStackTrace();
        }
    }
}


          public void run() {// Second thread in the Processor Class
    synchronized (this){
        RunnableController.setOutgoingQueue(generate(outgoingQueue));
    }
    notify();
}   
 }

我的任务和问题是：

1.控制器应处理线程Poller＆amp; amp;处理器，它应该只调用轮询器和放大器处理器线程

2.现在我的问题是如何让轮询线程等待3秒钟并且顺时针通知处理器。

我收到如下错误：

java.lang.IllegalMonitorStateException
    at java.lang.Object.wait(Native Method)
    at PollingSynchronizer.run(PollingSynchronizer.java:76)
    at java.util.concurrent.Executors$RunnableAdapter.call(Unknown Source)
    at java.util.concurrent.FutureTask$Sync.innerRun(Unknown Source)
    at java.util.concurrent.FutureTask.run(Unknown Source)
    at java.util.concurrent.ThreadPoolExecutor.runWorker(Unknown Source)
    at java.util.concurrent.ThreadPoolExecutor$Worker.run(Unknown Source)
    at java.lang.Thread.run(Unknown Source)

如何在此处实现异步处理？

Answer 1

您需要先阅读this之类的内容。如果不保持对象的监视器，则无法使用wait()。此外，从简短的一瞥看，您似乎在多线程上下文中使用非最终静态成员。尝试使线程安全。

非法监视器状态异常

1 个答案: