Question

我尝试从数据库本地向数据库服务器发送一些数据。数据库本地中的表名称是“收件箱”。 “收件箱”中的数据我转换为XML 这是代码（inboek2.php）本地pc中的脚本

<?php
mysql_connect('localhost', 'root', '');
mysql_select_db('sms');

header('Content-Type: text/xml');
echo "&lt;?xml version='1.0'?&gt;";

echo "<inbox>";

$query = "SELECT  inbox.id, ReceivingDateTime, SenderNumber, TextDecoded FROM inbox ORDER BY inbox.id";
$hasil = mysql_query($query);
while ($data = mysql_fetch_array($hasil))
{
   // representasi data sms
   echo "<data>";
   echo "<id>".$data['id']."</id>";
   echo "<tgl>".$data['ReceivingDateTime']."</tgl>";
   echo "<nope>".$data['SenderNumber']."</nope>";
   echo "<isi>".$data['TextDecoded']."</isi>";
   echo "</data>";
}
echo "</inbox>";
?>

脚本inboek2.php的结果，它将被脚本proses.php

捕获

这是代码proses.php（本地pc中的这个脚本）：

 <?php
    // koneksi ke mysql di server localhost
    mysql_connect('localhost', 'root', '');
    mysql_select_db('sms');

    // baca data XML dari script inboek2.php yang digenerate oleh data.php
    $dataxml = simplexml_load_file&#40;'http://localhost/baca/inboek2.php'&#41;;
    foreach($dataxml->data as $data)
    {

       $id = $data->id;
       $tgl = $data->tgl;
       $nope = $data->nope;
       $isi = $data->isi;

       $curlHandle = curl_init();
       $curResponse = curl_exec&#40;$curlHandle&#41;;
       curl_setopt($curlHandle, CURLOPT_URL, 'http://www.adibiken.com/SEM/kir.php');
       curl_setopt($curlHandle, CURLOPT_POSTFIELDS, 'id='.$id.'&amp;tgl='.$tgl.'&amp;nope='.$nope.'&amp;isi='.$isi);
       //and if i delete another variable atleast still the last one variable the data has been sucessfull sending whitout empty record ,,this is weird,,,,,
       curl_setopt($curlHandle, CURLOPT_HEADER, 0);
       curl_setopt($curlHandle, CURLOPT_RETURNTRANSFER, 1);
       curl_setopt($curlHandle, CURLOPT_TIMEOUT,30);
       curl_setopt($curlHandle, CURLOPT_POST, 1);
       curl_exec&#40;$curlHandle&#41;;
       curl_close($curlHandle);
       echo $curResponse;
    }
    ?>

和最后一个，这是HOSTING中kir.php的代码

<?php
include "koneksi.php";

$id = $_POST['id'];
$tgl = $_POST['tgl'];
$isi = $_POST['isi'];
$nope = $_POST['nope'];

// query insert data ke mysql
$quer = "INSERT INTO `adibiken_sem`.`inbox` (`id`,`tgl` ,`isi` ,`nope`) VALUES ( '".$id."','".$tgl."', '".$isi."', '".$nope."')";
mysql_query($quer);
?>

PROBELM：我该怎么做才能使变量：$id , $tgl, $isi, $nope已经成为SUCCESFULL发送到数据库而没有空的记录???

如果我删除另一个变量至少仍然是最后一个变量数据已成功发送whitout空记录,, 这很奇怪,,,,,

Answer 1

您可以通过以下方式查看：

if(isset($_POST['id'])){
    $id = $_POST['id']; 
}else{
    //the POST variable was empty, do something.
}

Answer 2

您可以尝试检查每个变量的长度，以确保在插入之前它们不是空的。这可以使用strlen或mb_strlen来完成。

http://www.php.net/manual/en/function.mb-strlen.php

http://php.net/manual/en/function.strlen.php

表DATABASE SERVER中的EMPTY RECORD使用cURL发送数据

2 个答案: