Question

我有一个Map [String，String]，我想按照特定的顺序打印它，具体取决于键。例如，我想打印id，name，address的值。所以我想将我的键与“id”，“name”，“address”匹配，然后在每个键上打印值。我有以下代码，但它不起作用：

articlesmap.keys match{
    case ("id") => println(articlesmap.get("id"))
        case ("name") => println(articlesmap.get("name"))
        case ("address") => println(articlesmap.get("address"))
 }

Answer 1

您可以使用for：

for { 
  k <- Seq("id", "name", "address") // the keys in the order you want to print them.
  v <- articlesmap.get(k) 
} println (k+ " is " + v)

如果您只想打印值，collect会很好：

Seq("id", "name", "address") collect articlesmap foreach println

collect优于map id，您无法确定某个密钥实际位于地图中。

Answer 2

这是我所知道的最简单的解决方案：

scala>  val keys = Seq("id", "name", "address") 
keys: Seq[java.lang.String] = List(id, name, address)

scala>  val articlesmap = Map("id" -> 1, "name" -> "john", "address" -> "some address")
articlesmap: scala.collection.immutable.Map[java.lang.String,Any] = Map(id -> 1, name -> john, address -> some address)

scala>  keys map articlesmap foreach println
1
john
some address

scala>  val keys = Seq("name", "id", "address")
keys: Seq[java.lang.String] = List(name, id, address)

scala>  keys map articlesmap foreach println
john
1
some address

Answer 3

变量articlesmap.keys的类型为Iterable[String]，但您的案例匹配在类型String上匹配。试试这个：

def mapTest(map: Map[String, String]) {
    map.keys.foreach {
      case ("id") => println(map.get("id"))
      case ("name") => println(map.get("name"))
      case ("address") => println(map.get("address"))
    }
  }                                            

  val mapper = Map("id" -> "123", "name" -> "Bob", "address" -> "123 Fake Street")

  mapTest(mapper)

  // => Some(123)
  //    Some(Bob)
  //    Some(123 Fake Street)

Answer 4

您可以创建OrderedMap，也可以对keys进行排序并处理该类型的结果。

Scala按顺序打印地图

4 个答案: