我正在开展这个项目以提高我的Java技能。我的目标是编写一个程序,从指定的文档或文本文件中读取行(取决于用户想要打开的行;分别为int 2或1)。然后要求用户输入他们的文档名称(没有文件扩展名) ),然后读取文档或文本文件中的第一行。我希望它能像用户想要的那样多次这样做。但是我在执行代码时不断获得NoSuchElementException
。
public class switches {
public static void main(String[] args) throws IOException {
Scanner input = new Scanner(System.in);
System.out.println("How many files would you like to scan?");
System.out.println("Enter # of files to scan: ");
int countInput = input.nextInt();
input.close();
for (int count = 0; count < countInput;) {
System.out.println("Please enter a file name to scan. ");
System.out.println("1 for .txt, 2 for .doc");
Scanner keyboard = new Scanner(System.in);
int choice = keyboard.nextInt();
switch (choice) {
default: {
do {
System.out.println("Please pick "
+ "either 1: txt or 2: doc");
choice = keyboard.nextInt();
} while (choice != 1 && choice != 2);
}
case 1: {
System.out.println("Txt file name:");
keyboard.nextLine();
String txtName = keyboard.nextLine();
File openTxtFile = new File("C:/Users/Hp/Documents/" + txtName
+ ".txt");
Scanner firstTxtLine = new Scanner(openTxtFile);
String printedTxtLine = firstTxtLine.nextLine();
firstTxtLine.close();
System.out.println("The first line " + "of your text file is: "
+ printedTxtLine);
keyboard.close();
count++;
break;
}
case 2: {
System.out.println("Doc file name:");
keyboard.nextLine();
String docName = keyboard.nextLine();
File openDocFile = new File("C:/Users/Hp/Documents/" + docName
+ ".doc");
Scanner firstLine = new Scanner(openDocFile);
String printedDocLine = firstLine.nextLine();
firstLine.close();
System.out.println("The first line"
+ " of your word document is: " + printedDocLine);
keyboard.close();
count++;
break;
}
}
}
}
}
答案 0 :(得分:2)
如果您删除第14行上的第input.close();
行。这可以解决您的问题。根据{{3}},如果输入用尽,它将抛出NoSuchElementException
- “。