我想将换行符转换为段落。
例如
$string = "1st paragraph
2nd paragraph
3rd paragraph
";
我想知道,
<p>1st paragraph</p>
<p>2nd paragraph</p>
<p>3rd paragraph</p>
和
$string = "1st paragraph
2nd paragraph
a line break
3rd paragraph
";
成,
<p>1st paragraph</p>
<p>2nd paragraph<br/>a line break</p>
<p>3rd paragraph</p>
是否可以使用regex
和reg_replace
?还是其他更好的东西 - xpath
?
我试过这个,但还没有结果,
echo preg_replace("'/^(.*?)(<br\s*\/?>\s*)+/'", "<p>$1</p>", nl2br($string));
答案 0 :(得分:15)
你可以反过来做:首先用段落替换多个换行符,然后用<br>
元素替换单个换行符。
$str = preg_replace('/\n(\s*\n)+/', '</p><p>', $str);
$str = preg_replace('/\n/', '<br>', $str);
$str = '<p>'.$str.'</p>';
您还应该首先将行结尾标准化(windows样式为unix样式):
function normalize($str) {
// Normalize line endings
// Convert all line-endings to UNIX format
$s = str_replace("\r\n", "\n", $str);
$s = str_replace("\r", "\n", $s);
// Don't allow out-of-control blank lines
$s = preg_replace("/\n{2,}/", "\n\n", $s);
return $s;
}
答案 1 :(得分:4)
又一个解决方案:
$string = preg_replace('/\n{2,}/', "</p><p>", trim($string));
$string = preg_replace('/\n/', '<br>',$string);
$string = "<p>{$string}</p>";