我有一个小问题写了正确的reg exp,我有一个字符串
2013-01-11 17:38:02.137759 some text leater
或
11 Jan 17:38:02 some text leater
所以我写了一个reg exp
(?:(?:(?:\d{4}-\d{2}-\d{2}\s\d{2}:\d{2}:\d{2}(?:\.\d+)?)\s(?:[^\s]+)\s(?:.\d+.)?\s?))?((?:(\d{4}-\d{2}-\d{2})\s\d{2}:\d{2}:\d{2}(?:\.\d+)?)|(?:(\w{3}\s+\d+)\s\d{2}:\d{2}:\d{2}))
示例结果是:
Array
(
[0] => Array
(
[0] => Jan 11 17:38:02
)
[1] => Array
(
[0] => Jan 11 17:38:02
)
[2] => Array
(
[0] =>
)
[3] => Array
(
[0] => Jan 11
)
)
或
Array
(
[0] => Array
(
[0] => 2013-01-11 17:38:02.137759
)
[1] => Array
(
[0] => 2013-01-11 17:38:02.137759
)
[2] => Array
(
[0] => 2013-01-11
)
[3] => Array
(
[0] =>
)
)
问题是结果我想跳过空场结果我该怎么做?
感谢您的帮助
答案 0 :(得分:1)
最简单的方法就是在结果上使用array_filter
:
array_filter($array, function ($piece) { return array_filter($piece); });