我试图在mysql中创建以下过程
PROCEDURE fix()
BEGIN
DECLARE event_id_ INT;
DECLARE gate_number INT;
DECLARE l_done INT DEFAULT 0;
DECLARE curs_event_id CURSOR FOR SELECT DISTINCT event_id FROM history_15min;
DECLARE curs_gate_number CURSOR FOR SELECT DISTINCT gate_number
FROM history_15min WHERE event_id =event_id_;
( -- HERE IS THE PROBLEM - event_id_ IS BLANK THERE FOR THE INNER LOOP RETURNS NO RESULTS ....)
DECLARE CONTINUE HANDLER FOR NOT FOUND SET l_done=1;
OPEN curs_event_id;
event_loop : LOOP
FETCH curs_event_id INTO event_id_;
IF l_done=1 THEN LEAVE event_loop;
END IF;
OPEN curs_gate_number;
gate_loop : LOOP
FETCH curs_gate_number INTO gate_number;
IF l_done=1 THEN LEAVE gate_loop;
END IF;
insert into t value ('1');
END LOOP gate_loop;
CLOSE curs_gate_number;
SET l_done=0;
END LOOP event_loop;
CLOSE curs_event_id;
END
有没有办法让第一个循环的结果成为第二个循环的变量?
答案 0 :(得分:0)
感谢CHill60,您的链接有我正在寻找的答案
这是执行嵌套循环的正确方法:
PROCEDURE fix()
BLOCK1: BEGIN
DECLARE colA_ INT;
DECLARE l_done INT DEFAULT 0;
DECLARE curs_colA CURSOR FOR SELECT DISTINCT colA FROM tableA;
DECLARE CONTINUE HANDLER FOR NOT FOUND SET l_done=1;
OPEN curs_colA;
first_loop : LOOP
FETCH curs_colA INTO colA_;
IF l_done=1 THEN LEAVE first_loop;
END IF;
BLOCK2: BEGIN
DECLARE calB_ INT;
DECLARE l_done INT DEFAULT 0;
DECLARE curs_calB CURSOR FOR SELECT DISTINCT calB FROM tableB WHERE colA = colA_;
DECLARE CONTINUE HANDLER FOR NOT FOUND SET l_done=1;
OPEN curs_calB;
second_loop : LOOP
FETCH curs_calB INTO calB_;
IF l_done=1 THEN LEAVE second_loop;
END IF;
insert into tmp value ('1');
END LOOP second_loop;
CLOSE curs_calB;
SET l_done=0;
END BLOCK2;
END LOOP first_loop;
CLOSE curs_colA;
END BLOCK1