Question

由于我的查询的性质，我的记录计数为3，也符合计数为2的标准，依此类推。我想知道是否可以查询“计数超过x且小于7”？我怎么能写这个。这是我目前的代码。

GROUP BY meetingID
HAVING COUNT( caseID )<4

我想要像

这样的东西

GROUP BY meetingID
HAVING COUNT( caseID )<4 AND >2

那样它只计算3

Answer 1

GROUP BY meetingID
HAVING COUNT(caseID) < 4 AND COUNT(caseID) > 2

Answer 2

没有必要进行两次检查，为什么不检查count = 3：

GROUP BY meetingID
HAVING COUNT(caseID) = 3

如果您想使用多项检查，则可以使用：

GROUP BY meetingID
HAVING COUNT(caseID) > 2
 AND COUNT(caseID) < 4

Answer 3

对于您的示例查询，唯一可能的值大于2且小于4是3，因此我们简化：

GROUP BY meetingID
HAVING COUNT(caseID) = 3

在一般情况下：

GROUP BY meetingID
HAVING COUNT(caseID) > x AND COUNT(caseID) < 7

或者（可能更容易阅读？），

GROUP BY meetingID
HAVING COUNT(caseID) BETWEEN x+1 AND 6

Answer 4

这样的东西？

HAVING COUNT(caseID) > 2
AND COUNT(caseID) < 4

Answer 5

在这里，我正在撰写完整的查询，这将清除您的所有怀疑

SELECT BillingDate,
       COUNT(*) AS BillingQty,
       SUM(BillingTotal) AS BillingSum
FROM Billings
WHERE BillingDate BETWEEN '2002-05-01' AND '2002-05-31'
GROUP BY BillingDate
HAVING COUNT(*) > 1
AND SUM(BillingTotal) > 100
ORDER BY BillingDate DESC

Answer 6

select CUSTOMER_CODE,nvl(sum(decode(TRANSACTION_TYPE,'D',AMOUNT)),0)) DEBIT,nvl(sum(DECODE(TRANSACTION_TYPE,'C',AMOUNT)),0)) CREDIT,
nvl(sum(decode(TRANSACTION_TYPE,'D',AMOUNT)),0)) - nvl(sum(DECODE(TRANSACTION_TYPE,'C',AMOUNT)),0)) BALANCE from TRANSACTION   
GROUP BY CUSTOMER_CODE
having nvl(sum(decode(TRANSACTION_TYPE,'D',AMOUNT)),0)) > 0
AND (nvl(sum(decode(TRANSACTION_TYPE,'D',AMOUNT)),0)) - nvl(sum(DECODE(TRANSACTION_TYPE,'C',AMOUNT)),0))) > 0

HAVING子句中的多个聚合函数

6 个答案: