Question

我的xml文件包含：

<?xml version="1.0" encoding="UTF-8"?>
<Contacts>
    <ContactGroup1>
        <person aa="sads">
            <name>Aghil</name>
            <emailid>aghilvarghese@gmail.com</emailid>
        </person>
    </ContactGroup1>  
</Contacts>

我试图通过以下java代码阅读：

        DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
        DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
        Document doc = (Document) dBuilder.parse(fXmlFile);
        doc.getDocumentElement().normalize();

        System.out.println("Root element :" + doc.getDocumentElement().getNodeName());

        NodeList nList = doc.getElementsByTagName("ContactGroup1");
        Node nNode = nList.item(0);//take first cgroup
        NodeList nl = (nNode.getChildNodes());
        System.out.println("nodes in ContactGroup1 : " + nl.getLength());
        for (int i = 0; i &lt; nl.getLength(); i++) {
            Node node = nl.item(i);
            System.out.println("node type is " + node.getNodeType() + " " + node.getNodeName());
         }

输出结果为：

Root element :Contacts
nodes in ContactGroup1 : 3
node type is 3 #text
node type is 1 person
node type is 3 #text

但在ContactGroup1中只有一个节点（即人），不是吗？为什么输错了？我该怎么做才能使它正确？

Answer 1

您可以跳过空文本节点。请检查此问题：How to remove #text from my Node parsing in Java dom xml parsing 所以基本上你应该检查节点是文本而空是然后跳过它。

java读取xml时输出错误

1 个答案: